Answer:
58 is greater than 51
Step-by-step explanation:
> is greater than and < is less than
X = -m/b.
Subtract z from both side and you get
-m= bx
Now divide both side by b and you get
-m/b= x
2/3 is your answer to the question
Answer:
x = 3.3 and -0.3
Step-by-step explanation:
Given the expression
1/x-4 + x/x-2=2/x^2-6x+8
Find the LCM
x-2+x(x-4)/(x-4)(x-2) = 2/x^2-6x+8
Since the denominator, are the same they cancels out
x +1 + x(x-4) = 2
x+1 + x²-4x = 2
x²-3x + 1 - 2 = 0
x² - 3x - 1 = 0
Factorize
x =3±√9+4/2
x =3±√13/2
x = 3±3.6/2
x= 6.6/2 and -0.6/2
x = 3.3 and -0.3
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
