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AVprozaik [17]
2 years ago
7

What is 1/2 x 9/10ths

Mathematics
2 answers:
Aleksandr-060686 [28]2 years ago
8 0

Answer: Awnser is 0.45 as a decimal and 9/20 as a fraction

Step-by-step explanation:


1. Multiply the numbers

((1/2)*9)/10 = (9/2)/10

2.divide the number's

(9/2)/10 = 9/20


Awnser = 9/20

Ymorist [56]2 years ago
8 0
The answer is 9/20






U basically like them up horizontally and multiply 1x9 and then 2x10
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What am I suppose to do so I can help you?
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2 years ago
Merle Fonda opened a new savings account. She deposited $40,000 at 10% compounded semiannually. At the start of the fourth year,
IrinaVladis [17]
Use compound interest formula  F=P(1+i)^n twice, one for each deposit and sum the two results.

For the P=$40,000 deposit,
i=10%/2=5%  (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253

For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6 
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913

Total amount after 6 years
= 71834.253 + 26801.913
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8 0
2 years ago
Given (-2, 4) (1, -2). Find the slope of the line
gavmur [86]

Answer:

-2

Step-by-step explanation:

We can find the slope of a line given two points from

m = (y2-y1)/(x2-x1)

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5 0
3 years ago
Read 2 more answers
The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab
Dmitry_Shevchenko [17]

Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.25

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when M = 0.1

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 2.575\sqrt{\frac{0.25*0.75}{n}}

0.1\sqrt{n} = 2.575{0.25*0.75}

\sqrt{n} = \frac{2.575{0.25*0.75}}{0.1}

(\sqrt{n})^{2} = (\frac{2.575{0.25*0.75}}{0.1})^{2}

n = 124.32

Rounding up

The minimum sample size needed is 125.

5 0
3 years ago
Only 30 minutes please help​
andrezito [222]

Answer:

B, and i don't for the second one

Step-by-step explanation:

4 0
3 years ago
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