What is the amplitude of y=1/2 sin2x

2 answers:

Colt1911 [192]3 years ago

8 0

$(-\frac{1}{2},\frac{1}{2})$
Amplitutde:
$(\frac{1}{2}-(-\frac{1}{2}))=1$
Normally for sinx amplitude is 2 (1 +1). In the case when it is half sine amplitude is halved, therefore 0.5 +0.5 = 1 Paramers alpha = 2x does not matter because it only stretches the graph horizontally.

Alborosie3 years ago

7 0

$for\ each\ \alpha \in R\ \ \ \ (for\ example\ \alpha =2x) \\\\the\ max\ of\ y=sin \alpha \ is\ 1\ \ \ and\ \ \ the\ min\ of\ y=sin \alpha \ is\ -1\\\\ the\ amplitude\ of \ \ \ \ y=sin \alpha \ \ \ \ is\ \ \ \ 1-(-1)=2\\\\\\then\ the\ amplitude\ of \ \ \ \ y= \frac{1}{2} sin 2x \ \ \ \ is\ \ \ \ \frac{1}{2} \cdot2= 1$

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alexandr402 [8]

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3 years ago

What is the quotient?

Sergio039 [100]

Answer: FIRST OPTION

Step-by-step explanation:

According the quotient of powers property, when you have the division of two powers with the same base, then you must subtract the exponents.

Therefore, keeping the property above on mind, you have that the quotient is the shown below:

$\frac{(-7)^2}{(-7)^{-1}}=(-7)^{(2-(-1))}=(-7)^{(2+1)}=(-7)^3=-343$