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4 years ago

PLEASE HELP ME PLEASE I BEG YOU

Mathematics

2 answers:

Tanya [424]4 years ago

6 0

Answer:

I think it's B.

Step-by-step explanation:

Because the equation is 1 - 0.144/24 should represent the amount of emails to be answered after one day.

Stolb23 [73]4 years ago

6 0

Answer:

D. The decay rate, which reveals the hourly rate of change in the number of customers whose subscriptions are due to be renewed.

Step-by-step explanation:

An exponential decay function is,

$f(x)=a(1-r)^x$

Where, a is initial value,

r is rate of change per period,

x is the number of periods,

(1-r) is decay factor that shows the periodic rate of change in the initial value.

Given expression that represents the number of such customers after n days is,

$15,000(1-\frac{0.144}{24})^{24n}$

By comparing,

15,000 is the initial number of customers who are due to be renewed,

$\frac{0.144}{24}$ is the change per hour in the number of customers,

24n is the total number of hours,

$(1-\frac{0.144}{24})$ is the decay factor or decay rate that reveals the hourly rate of change in the number of customers,

Hence, option 'D' is correct.

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qaws [65]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

Given that $(b-c)^2, (c-a)^2 , (a-b)^2$ are in AP

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Now

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc$

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3 years ago

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3 years ago

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KATRIN_1 [288]

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