If this is your equation:

Solution:
LCD for 5 and 5x is 5x




←cross product
20x + 30 = 5x² + 25x ←simplify with distributive property
0 = 5x² + 5x - 30 ←use inverse operations to collect all terms on one side
0 = x² + x - 6 ←if possible divide by numerical GCF (This case 5)
0 = (x + 3)(x - 2) ←Factor
x = -3 or x = 2
Please check by substitution in original equation... Both work
Answer:
It isn't possible.
Step-by-step explanation:
Let G be a graph with n vertices. There are n possible degrees: 0,1,...,n-1.
Observe that a graph can not contain a vertice with degree n-1 and a vertice with degree 0 because if one of the vertices has degree n-1 means that this vertice is adjacent to all others vertices, then the other vertices has at least degree 1.
Then there are n vertices and n-1 possible degrees. By the pigeon principle there are two vertices that have the same degree.
Area = length x width
24 = (n-3) x 2
24 = 2n -6
2n = 30
n = 15
Length is 15-3 =12, width is 2
24 = 12 x 2
Answer:
wheres the picture?
Step-by-step explanation:
Sec is the length of the hypotenuse divided by the length of the adjacent side.
Meaning divide 20/16
Meaning your secant or sec is 1.25 or 1 1/4