7. 4y(5y - 11) – 2y(3y + 10)
1 answer:
Answer:
Step-by-step explanation:
Hello!
4y(5y - 11)
Distribute the 4y
4y * 5y = 20y^2
4y * -11 = -44y
Put it together
20y^2 - 44y
2y(3y + 10)
Distribute the -2y
-2y * 3y = -6y^2
-2y * 10 = -20y
Put it gether
-6y^2 - 20y
Put it all together
20y^2 - 44y - 6y^2 - 20y
Combine like terms
14y^2 - 64y
The answer is
Hope this helps!
You might be interested in
Substitute this into the parabolic equation,
We're told the line intersects
twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know
We can tell from the quadratic equation that has its vertex at the point (3, 6). Also, note that
and
so the furthest to the right that extends is the point (5, 2). The line
passes through this point for
. For any value of
, the line
passes through
either only once, or not at all.
So ; in set notation,