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Soloha48 [4]
3 years ago
14

7. 4y(5y - 11) – 2y(3y + 10)

Mathematics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

14y^{2} -64y

Step-by-step explanation:

Hello!

4y(5y - 11)

Distribute the 4y

4y * 5y = 20y^2

4y * -11 = -44y

Put it together

20y^2 - 44y

2y(3y + 10)

Distribute the -2y

-2y * 3y = -6y^2

-2y * 10 = -20y

Put it gether

-6y^2 - 20y

Put it all together

20y^2 - 44y - 6y^2 - 20y

Combine like terms

14y^2 - 64y

The answer is 14y^{2} -64y

Hope this helps!

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