7. 4y(5y - 11) – 2y(3y + 10)
1 answer:
Answer:
Step-by-step explanation:
Hello!
4y(5y - 11)
Distribute the 4y
4y * 5y = 20y^2
4y * -11 = -44y
Put it together
20y^2 - 44y
2y(3y + 10)
Distribute the -2y
-2y * 3y = -6y^2
-2y * 10 = -20y
Put it gether
-6y^2 - 20y
Put it all together
20y^2 - 44y - 6y^2 - 20y
Combine like terms
14y^2 - 64y
The answer is
Hope this helps!
You might be interested in
Answer:
16.28 mph ; 79.38°
Step-by-step explanation:
Given the following :
Speed of child due east = 3mph
Speed of ship due North = 16mph
Relative speed of th child is obtained by using Pythagoras rule to find the hypotenus
Relative Speed = Sqrt(3² + 16²)
Relative Speed = sqrt(9 + 256)
= sqrt(265)
= 16.2788 mph
= 16.28 mph
From trigonometry ;
Tanθ = opposite / Adjacent
Tanθ = (16 / 3)
Tanθ = 5.333
θ = tan^-1(5.333)
θ = 79.379°
θ = 79.38°
