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gregori [183]
1 year ago
11

I need help I’m stuck

Mathematics
1 answer:
marysya [2.9K]1 year ago
6 0

Answer:

3rd one

Step-by-step explanation:

i did it

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Bernita and Rosalee are comparing their heights. Bernita is 1.63
aev [14]

Answer:

1.44

Step-by-step explanation:

1.63-.19= 1.44

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3 years ago
Factorize the given expression:<br> 27x3 - 63x2 + 49x – 343 27
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49x−9306 I’m not sure
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2 years ago
Plz help me.
Vlad [161]
Assuming you want to find x?
You know that the angles at C and B have to be the same (6x) because it’s an isosceles triangle (as indicated by the lines going through AC and AB), and angles in a triangle add to 180*

So 3x + 6x + 6x = 180*
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2 years ago
NEED HELP ASAP WILL GIVE BRAINLY IF CORRECT 20 POINTS
Lunna [17]
The answer is the second one
7 0
3 years ago
Read 2 more answers
A 5.1-ft-tall person walks away from a 12-ft lamppost at a constant rate of 3.9 ft/sec. What is the rate that the tip of the per
nekit [7.7K]

Answer:

6.78ft/sec

Step-by-step explanation:

From the question, dx/dt= 3.9 ft/sec

We are looking for Dy/dt

From geometry,vof this case the relationship between x and y is needed here, there is two similar triangle that exhibited by the man and the lamb

12/y= 5.1/(y-x)

Then ,cross multiply, we have

12(y-x)=5.1y

12y-12x=5.1y

12y-5.1y=12x

6.9y=12x

y=( 12/6.9)x

Differentiating implicitly the bother sides with respect to t, we have

Dy/dt= ( 12/6.9)dx/dt

But dx/dt= 3.9 ft/sec

Then Dy/dt= ( 12/6.9)× 3.9

Dy/dt=6.78ft/sec

Hence, the rate that the tip of the person's shadow moves away from the lamppost when the person is 9 ft away from the lampost is 6.78ft/sec

CHECK THE ATTACHMENT FOR THE FIQURE

6 0
3 years ago
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