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Alexandra [31]
3 years ago
11

Mary tutors english. For each hour that she tutors she earns 40 dollars. Let E be her earnings (in dollars) after tutoring for H

hours. Write an equation relating E to H. Then use this equation to find marys earnings after tutoring for 13 hours
Mathematics
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

A.) 40(t) = E

B.) 520

Step-by-step explanation:

t is for time, E is the total, H is the hourly rate.

plug in the numbers to get 40(13) = h and solve for H and you get 520

<em>-- Brainliest answer is much appreciated! :)</em>

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5 pointsWhich is the image of vertex Lafter the triangle is rotated 180 degrees about the origin?
Anastasy [175]

The image of vertex L after the triangle is rotated 180 degrees about the origin= (-2, -1).

Option B.

First let's stae the the original location of the figure on the graph.

From the graph:

L (2, 1)

W(1, -3)

O (-1, -2)

A rotation of 180 degrees about the origin will change the x and y axis of each location to the opposite of those numbers;

Positive numbers becomes negative and negative numbers becomes positive.

The new location for L = L'

L' = (-2, -1)

The new location for W = W'

W' = (-1, 3)

The new location for O = O'

O' = (1, 2)

Hence, the image of vertex L after the triangle is rotated 180 degrees about the origin= (-2, -1).

Option B.

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1 year ago
A vase can hold 9 flowers. If a florist had 878 flowers she wanted to put equally into vases, how many flowers would be in the l
zavuch27 [327]
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Graph the proportional relationship, y = 5x.
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Answer:

Hope the graph below helps.

Step-by-step explanation:

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3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
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