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natta225 [31]
3 years ago
8

A coordinate plane graph is shown. Point C is at negative 4 comma 3. Point D is at 1 comma 0. A segment connects the two points.

What is the distance (in units) between points C and D? Round your answer to the nearest hundredth. 4.54 units 5.00 units 5.83 units 34.00 units
Mathematics
2 answers:
Viktor [21]3 years ago
4 0
The distance between two points knowing theirs coordinates:

AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>C(-4,3) & D(1,0) Given
                                                C(x₁,y₁) & D(x₂,y₂)

AB =√[(1-(-4))²+(0-3)²] =√(34) = 5.381 ≈ 5.83 units
madam [21]3 years ago
3 0

Answer:

The distance between two points knowing theirs coordinates:

AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>C(-4,3) & D(1,0) Given

                                               C(x₁,y₁) & D(x₂,y₂)

AB =√[(1-(-4))²+(0-3)²] =√(34) = 5.381 ≈ 5.83 units

Step-by-step explanation:

it is this bc i do flvs and its correct :)

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Rs = 8y + 4 , ST = 4y + 8 , and RT = 36 , find the value of y
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I assume that you meant RS and ST are segments of RT.  If that is true then:

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8y+4+4y+8=36  combine like terms on left side

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If N is the population of the colony and t is the time in​ days, express N as a function of t. Consider Upper N 0 is the origina
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Answer:

(a)N(t)=Noe^{kt}

(b)5,832 Mosquitoes

(c)5 days

Step-by-step explanation:

(a)Given an original amount N_o at t=0. The population of the colony with a growth rate k \neq 0, where k is a constant is given as:

N(t)=Noe^{kt}

(b)If N_o=1000 and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)

Therefore, our model is:

N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t

In 3 days time

N(3)=1000\cdot1.8^3=5832

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days

In approximately 5 days, the population of mosquitoes will be 20,000.

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Step-by-step explanation:

ABCDE = ΔEAD + ΔDAC + ΔCAB

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6 0
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What is the length of segment AB
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Answer: \large \boldsymbol {C) \ AB=\sqrt{41} }

Step-by-step explanation:

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