In 1993, Moose Population: 3280
In 1999, population became: 4960
P (Population) , t (years)
t = 6 —> 4960 - 3280 = 1680
Average Change —> 1680/6 = 280 moose/year
• In terms of 1990:
t = 3 —> 3280-3 (280)
P(1990) = 2440
P(t) = 2440 + 280t
• In 2003; t = 13
P(13) = 2440 + 280 (13)
P(13) = 2440 + 3640
P(13) = 6080
• Moose population in 2003
= 6080
Answer:
24/49
Step-by-step explanation:
Let's add the terms and see if there's a pattern
Suppose we say the sum of n terms is (n/(2n+1)), the next term in the series will be 1/((2n+1)(2n+3)) and adding that to the presumed sum gives ...
Then it appears the sum of n terms is (n/(2n+1)). So, the sum of 24 terms is ...
Answer:
a) $1199.10
b) interest: $1000.00
c) principal: $199.10
Step-by-step explanation:
a) The monthly payment can be found using a financial calculator or using the amortization formula:
A = P(r/12)/(1 -(1+r/12)^(-12t))
for Principal P, annual interest rate r, and time t years.
Filling in the given values and doing the arithmetic yields ...
A = $200,000(0.06/12)/(1 -(1+0.06/12)^(-12·30)) = 1000/(1 -1.005^-360)
A ≈ $1199.10
__
b) The first month's interest is the monthly interest rate times the initial loan balance:
= (0.06/12)·(200,000) = 1000.00 . . . . dollars in interest
__
c) The first month's payment to principal is the difference between the payment amount and the amount to interest:
$1199.10 -1000 = $199.10 . . . . . first month's payment on principal
Answer:
I think it's A AND C. The diameter is just the radius multiplied by 2 at the end of the day.B is just wrong.
The answer is D dilation and reflection
