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Nookie1986 [14]
4 years ago
7

Draw a line representing the "run" and a line representing the "rise" of the line. State the slope of the line in simplest form.

​

Mathematics
1 answer:
notsponge [240]4 years ago
5 0

Answer:

1

Step-by-step explanation:

think of it as vertical over horizontal v/h vertical=1 horizontal=1 so 1/1=1

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I need help I dont know how to do this
Nikolay [14]

Answer:

9.2

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
For f(x)=2x+1 and g(x)=x^2-7, find (f.g)(x)
hram777 [196]

Option C (in the figure) is correct.

Step-by-step explanation:

We need to find (f.g)(x)

Given that f(x)=2x+1\\g(x)= x^2-7

Now finding (f.g)(x)

(f.g)(x)= f(x).g(x)

(f.g)(x)= (2x+1)(x^2-7)\\(f.g)(x)=2x(x^2-7)+1(x^2-7)\\(f.g)(x)=2x^3-14x+x^2-7\\(f.g)(x)=2x^3+x^2-14x-7

So, (f.g)(x)=2x^3+x^2-14x-7

Option C (in the figure) is correct.

Learn more about Composite Functions at:

brainly.com/question/10772025

brainly.com/question/10541435

Keywords: Composite function

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8 0
3 years ago
Last year Tyler used 60 feet of fencing to enclose a rectangular garden with an area of 200 ft². This year Tyler plans to use 12
Alik [6]

Answer:

Area of new garden = 800 ft²

Step-by-step explanation:

Given:

Old fencing = Parameter of old garden = 60 ft

Area of old garden = 200 ft

Find:

Area of new garden if Parameter of new garden is 120 ft

Computation:

Assume;

Length of old garden = l

Width of old garden = b

So,

2[l + b] = 60

l + b = 30

l = 30 - b

Area of old garden = 200 ft

l x b = 200

So,

(30 - b)b = 200

b² - 30b + 200 = 0

b² - 20b - 10b + 200

b(b-20) - 10(b-20)

(b-20)(b-10)

So,

Width of old garden = 10 ft

Length of old garden = 20 ft

New parameter is double

So,

Width of new garden = 10 x 2 = 20 feet

Length of old garden = 20 x 2 = 40 feet

Area of new garden = l x b

Area of new garden = 20 x 40

Area of new garden = 800 ft²

4 0
3 years ago
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