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Julli [10]
4 years ago
14

Select the correct response for three consecutive integers whose sum is 42. A) 12,13,14. B)9,10,11. C)13,14,15 D)14,15,16

Mathematics
2 answers:
nikitadnepr [17]4 years ago
7 0
Hello,
it must be:
x+(x+1)+(x+2)=42
from which:
x+x+1+x+2=42;
3x+3=42;
3x=42-3;
3x=39;
x=39:3=13
the first number is 13;
the second number is:
13+1=14
The third number is:
13+2=15

The answer is C.

Bye :-)
jeka944 years ago
4 0
I feel like the answer would be <span>A) 12,13,14.

</span>
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➷ Just multiply the price by 3:

1.35 x 3 = 4.05

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6 0
3 years ago
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what is the prime factorization of 55^5 x 65 x 9^15 and why? A. 3^15 * 5^6 *11^5*13 B. 3^30 *5^6 *11^5 *13 C.3^30 * 5^6 *11 * 13
leonid [27]

Answer:

B

Step-by-step explanation:

1. Lets focus on 55^5

55^5 = 11^5 * 5^5

2. now on 65

65 = 5 * 13

3. now on 9^15

9^15=(3^2)^15 = 3^30

4. combine all three parts

11^5 * 5^5 * 5 * 13 * 3^30 = 11^5*5^6*13*3^30

so our answer is B

7 0
3 years ago
a nature clubs has 37 member.each member receives 15 fish to put aquarium . if 20 of total number of fish or put into a fish bow
PilotLPTM [1.2K]

Answer:

74

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5 0
3 years ago
Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result
Vaselesa [24]

<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) (10-x)(12-x)=15

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

length=10-x\\breadth=12-x

According to question , Area of new image is :

⇒ Area = \frac{1}{8}Length(breadth)

⇒ Area = \frac{1}{8}(10)(12)

⇒ Area = 15

So the equation will be :

⇒ (10-x)(12-x)=15

b. Find the dimensions of the reduced image

Let's solve :  (10-x)(12-x)=15

⇒ 120-10x-12x+x^2=15

⇒ 120-22x+x^2=15

⇒ x^2-22x+105=0

By Quadratic formula :

⇒ x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x = \frac{22 \pm8 }{2}

⇒ x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}

⇒ x = 15 , x =7

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ x =7

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

5 0
3 years ago
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Olegator [25]
S = 92

Explanation: I just know
4 0
3 years ago
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