Question

The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the length and width of the playground

Answer 1

L=16
W=21

Set up a systems of equations: 
x=length 
y=width 

xy=336
x+5=y

Use substitution to solve: 
x(x+5)=336
x^2+5x=336 

Solve using factoring: 
x^2+5x-336=0
(x-16)(x+21)=0
x=16 and x= -21 
Since length can't be negative, l=16 

To find width, plug length into the first equation: 
(16)y=336
y=21 

So...
L=16
W=21

Answer 2

L=16

W=21

Set up a systems of equations: 

x=length 

y=width 

xy=336

x+5=y

Use substitution to solve: 

x(x+5)=336

x^2+5x=336 

Solve using factoring: 

x^2+5x-336=0

(x-16)(x+21)=0

x=16 and x= -21 

Since length can't be negative, l=16 

To find width, plug length into the first equation: 

(16)y=336

y=21 

So...

L=16

W=21