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Snowcat [4.5K]
3 years ago
7

The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the length and width of th

e playground
Mathematics
2 answers:
kondaur [170]3 years ago
7 0
L=16
W=21

Set up a systems of equations: 
x=length 
y=width 

xy=336
x+5=y

Use substitution to solve: 
x(x+5)=336
x^2+5x=336 

Solve using factoring: 
x^2+5x-336=0
(x-16)(x+21)=0
x=16 and x= -21 
Since length can't be negative, l=16 

To find width, plug length into the first equation: 
(16)y=336
y=21 

So...
L=16
<span>W=21</span>
fredd [130]3 years ago
3 0

<u><em>L=16</em></u>

<u><em>W=21</em></u>

<u><em></em></u>

<u><em>Set up a systems of equations: </em></u>

<u><em>x=length </em></u>

<u><em>y=width </em></u>

<u><em></em></u>

<u><em>xy=336</em></u>

<u><em>x+5=y</em></u>

<u><em></em></u>

<u><em>Use substitution to solve: </em></u>

<u><em>x(x+5)=336</em></u>

<u><em>x^2+5x=336 </em></u>

<u><em></em></u>

<u><em>Solve using factoring: </em></u>

<u><em>x^2+5x-336=0</em></u>

<u><em>(x-16)(x+21)=0</em></u>

<u><em>x=16 and x= -21 </em></u>

<u><em>Since length can't be negative, l=16 </em></u>

<u><em></em></u>

<u><em>To find width, plug length into the first equation: </em></u>

<u><em>(16)y=336</em></u>

<u><em>y=21 </em></u>

<u><em></em></u>

<u><em>So...</em></u>

<u><em>L=16</em></u>

<u><em>W=21</em></u>

<u><em /></u>

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