Answer:
T1 = 975 / (205 + V) flying with wind
T2 = 975 / (205 - V) flying against wind
T2 = T1 + 2
975 * {1 / (205 - V) - 1 / (205 + V)] = 2
(205 + V + V -205) / (205^2 - V^2) = 2 / 975
V^2 + 975 V - 42025 = 0 rearranging
V = 41.3
Values of flying are 246.3 and 163.7
Check:
T1 = 975 / 246.3 = 3.96 hrs
T2 = 975 / 163.7 = 5.96 hrs
Step-by-step explanation:
1/sin10-√3/cos10
= (cos10 - √3sin10)/cos10sin10
multiplying 1/2 in denominator and numerator
= {(cos10/2) - (√3sin10/2)}/(cos10sin10/2)
= (cos60cos10 - sin60sin10)/(cos10sin10/2)
= cos(60 + 10)/(cos10sin10/2)
= cos70/(cos10sin10/2)
= 2cos70/cos10sin10
multiplying 2 on numerator and denominator
= 4cos70/2sin10cos10
=4cos70/sin20
=4cos70/cos70
= 4 proved
Answer:
angle of depression = 2.1⁰
Step-by-step explanation:
1 mile = 5280 ft
Hence angle of depression = 90 - ∅
Where ∅ is angle of depression
Tan ∅ = (5 x 5280)/ 950
∅ = Tan₋¹ (27.789474) = 87.9⁰
Hence angle of depression = 90 - 87.9 = 2.1⁰
Answer:
A and B
Step-by-step explanation:
We need the half-life of C-14 which is 5,730 years.
Now, we will need a half-life equation:
elapsed time = half-life * log (bgng amt / ending amt) / log 2
We'll say beginning amount = 100 and ending amount = 41
elapsed time = 5,730 * log (100/41) / log 2
elapsed time = 5,730 * log (
<span>
<span>
<span>
2.4390243902
</span>
</span>
</span>
) / 0.30102999566
elapsed time = 5,730 * 0.38721614327 / 0.30102999566
elapsed time =
<span>
<span>
</span></span><span><span><span>5,730 * 1.2863041851
</span>
</span>
</span>
<span>elapsed time = 7,370.523 years
Source:
http://www.1728.org/halflife.htm </span>
