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Olenka [21]
3 years ago
12

Solve equation algebraically 3 root x-2x=-5

Mathematics
1 answer:
koban [17]3 years ago
4 0

Answer:

<h3>The value of x is - 1 , - 6.25</h3>

Step-by-step explanation:

Given linear equation as :

3\sqrt{x} - 2 x = - 5

<u>Rearranging the equation</u>

3\sqrt{x} = 2 x - 5

<u>Taking square both side</u>

(3\sqrt{x} )^{2} = (2 x - 5)²

Or, 9 x = 4 x² - 20 x + 25                    [ from (a + b)² = a² + 2ab + b² ]

Or,  4 x² - 20 x - 9 x + 25 = 0

Or, 4 x² - 29 x + 25 = 0      

The equation is in the form of quadratic equation i.e a x² + b x + c = 0      

So, x = \frac{- b\pm \sqrt{b^{2} - 4\times a\times c}}{2\times a}

Or, x = \frac{- (-29)\pm \sqrt{(-29)^{2} - 4\times 4\times 25}}{2\times 4}

Or, x = \frac{- 29\pm \sqrt{841 - 400}}{8}

Or, x = \frac{- 29\pm \sqrt{441}}{8}

Or, x = \frac{-29+21}{8} , \frac{-29-21}{8}

Or, x = - 1 , - 6.25

So, The value s of x = - 1 , - 6.25

Hence, The value of x is - 1 , - 6.25 Answer

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Step-by-step explanation:

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Hence, L reaches its maximum value when θ = 0 because cos²(0) = 1.

I hope it helps you!

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