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Lynna [10]
3 years ago
11

N industry consists of three firms with sales of $360,000, $650,000, and $265,000.

Business
1 answer:
Yanka [14]3 years ago
5 0

These three together form total market, so here we have to add up everything to know volume of the market

A+B+C = 1,275,000 is the total market

Then we have to calculate individual market share

which would eb 1) 28.2%, 2) 50.9%, 3) 20.8%

This can be calcualated by simple percetage calculation. ( 1275000-360000/1275000*100)-100 will give what share each has.

Then we apply HHI formula

HHI = s1^2 + s2^2 + s3^2 + ... + sn^2

HHi is nothing but squaring of each of the percentages and adding them up

(28.2)2 +(50.9)2 +(20.8)2

812+2590+432 = 3834

HHI of 3834 shows it is highly competitve market.

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yaroslaw [1]

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a) Probability of prostrate cancer given a positive test is P(C|+) = 0.0213

b) Probability of cancer given a negative test is P(C|-) = 0.0161

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d) Probability of cancer given a negative test is P(C|-) = 0.2553

Explanation:

Probability male patient has prostate cancer, P(C) = 0.02

Probability male patient does not have prostrate cancer P(C') = 1 - 0.02 = 0.98

Probability of a positive test given there is no cancer, i.e. P(false positive) = P(+|C') = 0.75

P(negative test given there is cancer) = P(false negative) = P(-|C) = 0.2

P(negative test given there is no cancer) is the complement of P(+|C') = P(-|C') = 1 - 0.75 = 0.25

Probability of positive test given there is prostrate cancer, P(+|C) is the complement of P(-|C), = 1 - 0.2 = 0.8.

a) Probability of prostrate cancer given a positive test is P(C|+)

According to Baye's theorem, P(C|+) = P(+|C)P(C)/P(+)

For P(+), we use the Law Of Total Probability: P(+) = P(+|C)P(C) + P(+|C')P(C')

P(+) = (0.8 * 0.02) + (0.75 * 0.98) = 0.751

Therefore, P(C|+) = P(+|C)P(C)/P(+)

P(C|+) = (0.8 * 0.02)/0.751 = 0.0213

b) Probability of cancer given a negative test is P(C|-)

According to Baye's theorem, P(C|-) = P(-|C)P(C)/P(-)

P(-) = P(-|C)P(C) + P(-|C')P(C')

P(-) = (0.2 * 0.02) + (0.25 * 0.98) = 0.249

Therefore, P(C|-) = (0.2 * 0.02)/0.249

P(C|-) = 0.0161

Part 2: Given the following;

Probability male patient has prostate cancer, P(C) = 0.3

Probability male patient does not have prostrate cancer P(C') = 1 - 0.3 = 0.70

Probability of a positive test given there is no cancer, i.e. P(false positive) = P(+|C') = = 0.75

P(negative test given there is cancer) = P(false negative) = P(-|C) = 0.2

P(negative test given there is no cancer) is the complement of P(+|C') = P(-|C') = 1 - 0.75 = 0.25

Probability of positive test given there is prostrate cancer, P(+|C) is the complement of P(-|C), = 1 - 0.2 = 0.8.

c) Probability of prostrate cancer given a positive test is P(C|+)

According to Baye's theorem, P(C|+) = P(+|C)P(C)/P(+)

For P(+), we use the Law Of Total Probability: P(+) = P(+|C)P(C) + P(+|C')P(C')

P(+) = (0.8 * 0.3) + (0.75 * 0.7) = 0.751

Therefore, P(C|+) = P(+|C)P(C)/P(+)

P(C|+) = (0.8 * 0.3)/0.765 = 0.3137

d) Probability of cancer given a negative test is P(C|-)

According to Baye's theorem, P(C|-) = P(-|C)P(C)/P(-)

P(-) = P(-|C)P(C) + P(-|C')P(C')

P(-) = (0.2 * 0.3) + (0.25 * 0.7) = 0.235

Therefore, P(C|-) = (0.2 * 0.3)/0.235

P(C|-) = 0.2553

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Answer:

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