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2 years ago

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The length of a side of the base of a square pyramid is 10 inches. The height of each triangular face is 12 inches. What is the

surface area of the pyramid?
A. 70 in.2

B. 160 in.2

C. 300 in.2

D. 340 in.2

2 answers:

galben [10]2 years ago

8 0

Answer:

it's D

Step-by-step explanation:

sergeinik [125]2 years ago

5 0

Answer : D . 340 in. 2

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Who do you solve 7/12 divde by 2/5

eduard

7 2
12 5
Do the reciprocal!
7 5
12 2
And just multiply and you get 35/24

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2 years ago

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Use the replacement set {3, 4, 9} to find the solution of the equation below.<br> 3n−18=9

Mrac [35]

Answer:

$n=9$

Step-by-step explanation:

$3n-18=9$

$3n+18=$ +18

$3n=27$

$3(9)=27$

$n=9$

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2 years ago

Find the slope \mathrm{m}m of the line in the graph below. \mathrm{m} =m=

yulyashka [42]

Answer:

$m=4$ or $m=\frac{4}{1}$

Step-by-step explanation:

To find slope we use the slope formula

$m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

Two points on the line we can classify are (3,4) and (4,8)

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2 years ago

The following graphs have a scale assigned to them: The area of each grid

dezoksy [38]

The graphs that are density curves for a continuous random variable are: Graph A, C, D and E.

<h3>How to determine the density curves?</h3>

In Geometry, the area of the density curves for a continuous random variable must always be equal to one (1). Thus, we would test this rule in each of the curves:

Area A = (1 × 5 + 1 × 3 + 1 × 2) × 0.1

Area A = 10 × 0.1

Area A = 1 sq. units (True).

For curve B, we have:

Area B = (3 × 3) × 0.1

Area B = 9 × 0.1

Area B = 0.9 sq. units (False).

For curve C, we have:

Area C = (3 × 4 - 2 × 1) × 0.1

Area C = 10 × 0.1

Area C = 1 sq. units (False).

For curve D, we have:

Area D = (1 × 4 + 1 × 3 + 1 × 2 + 1 × 1) × 0.1

Area D = 10 × 0.1

Area D = 1 sq. units (True).

For curve E, we have:

Area E = (1/2 × 4 × 5) × 0.1

Area E = 10 × 0.1

Area E = 1 sq. units (True).

Read more on density curves here: brainly.com/question/26559908

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1 year ago

These data can be approximated quite well by a N(3.4, 3.1) model. Economists become alarmed when productivity decreases. Accordi

CaHeK987 [17]

Answer:

First part

$P(X< 3.4-0.6*3.1) = P(X$

And for this case we can use the z score formula given by:

$z = \frac{x- \mu}{\sigma}$

And using this formula we got:

$P(X$

And we can use the normal standard table or excel and we got:

$P(Z$

Second part

For the other part of the question we want to find the following probability:

$P(-1.715$

And using the score we got:

$P(-1.715$

And we can find this probability with this difference:

$P(-1.65< Z< 1.210)=P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the data of a population, and for this case we know the distribution for X is given by:

$X \sim N(3.4,3.1)$

Where $\mu=3.4$ and $\sigma=3.1$

First part

And for this case we want this probability:

$P(X< 3.4-0.6*3.1) = P(X$

And for this case we can use the z score formula given by:

$z = \frac{x- \mu}{\sigma}$

And using this formula we got:

$P(X$

And we can use the normal standard table or excel and we got:

$P(Z$

Second part

For the other part of the question we want to find the following probability:

$P(-1.715$

And using the score we got:

$P(-1.715$

And we can find this probability with this difference:

$P(-1.65< Z< 1.210)=P(Z$

8 0

2 years ago