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irga5000 [103]
3 years ago
10

A screening test for a newly discovered disease was evaluated in order to determine how well the test performs. Investigators ad

ministered the test to a random sample of 900 people. Of the participants with the disease, 150 tested positive and 60 tested negative. Of those without the disease, 50 tested positive. What is the sensitivity of the screening test?
A. 7.14%
B. 71.43%
C. 7.50%
D. 75.00%
E. None of the above
Mathematics
1 answer:
saw5 [17]3 years ago
5 0

Answer:

B. 71.43%

Step-by-step explanation:

The sensitivity is the probability that a test will indicate 'disease' among those with the disease, that is, the test has a positive results:

In this problem, we have that:

150 people with the disease tested positive and 60 tested negative. So the sensitivity is:

S = 100*\frac{150}{210} = 71.43

The correct answer is:

B. 71.43%

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Resistors for electronic circuits are manufactured on a high-speed automated machine. The machine is set up to produce a large r
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Answer:

See explanation

Step-by-step explanation:

Given

See attachment for proper presentation of question

Required

Mean and Range

To do this, we simply calculate the mean and the range of each row.

\bar x = \frac{\sum x}{n} ---- mean

Where:

n = 4 ---- number of rows

R = Highest - Lowest --- range

So, we have:

Sample 1

\bar x_1 = \frac{1027+ 994 +977 +994 }{4}

\bar x_1 = 998

R_1 = 1027- 994

R_1 = 33

Sample 2

\bar x_2 = \frac{975 +1013 +999 +1017}{4}

\bar x_2 = 1001

R_2 =  1017 - 975

R_2 = 42

Sample 3

\bar x_3 = \frac{988 +1016 +974 +997}{4}

\bar x_3 = 993.75

R_3 = 1016-974

R_3 = 42

Sample 4

\bar x_4 = \frac{998 +1024 +1006 +1010}{4}

\bar x_4 = 1009.5

R_4 = 1024 -998

R_4 = 26

Sample 5

\bar x_5 = \frac{990 +1012 +990 +1000}{4}

\bar x_5 = 998

R_5 = 1012 -990

R_5 = 22

Sample 6

\bar x_6= \frac{1016 + 998 +1001 +1030}{4}

\bar x_6= 1011.25

R_6= 1030-998

R_6= 32

Sample 7

\bar x_7 = \frac{1000 +983 +979 +971}{4}

\bar x_7 = 983.25

R_7 = 1000-971

R_7 = 29

Sample 8

\bar x_8 = \frac{973 +982 +975 +1030}{4}

\bar x_8 = 990

R_8 = 1030-973

R_8 = 57

Sample 9

\bar x_9 = \frac{992 +1028 +991 +998}{4}

\bar x_9 = 1002.25

R_9 = 1028 -991

R_9 = 37

Sample 10

\bar x_{10} = \frac{997 +1026 +972 +1021}{4}

\bar x_{10} = 1004

R_{10} = 1026 -972

R_{10} = 54

Sample 11

\bar x_{11} = \frac{990 +1021 +1028 +992}{4}

\bar x_{11} = 1007.75

R_{11} = 1028 -990

R_{11} = 38

Sample 12

\bar x_{12} = \frac{1021 +998 +996 +970}{4}

\bar x_{12} = 996.25

R_{12} = 1021 -970

R_{12} = 51

Sample 13

\bar x_{13} = \frac{1027 +993 +996 +996}{4}

\bar x_{13} = 1003

R_{13} =1027 -993

R_{13} =34

Sample 14

\bar x_{14} = \frac{1022 +981 +1014 +983}{4}

\bar x_{14} = 1000

R_{14} = 1022 -981

R_{14} = 41

Sample 15

\bar x_{15} = \frac{977 +993 +986 +983}{4}

\bar x_{15} = 984.75

R_{15} = 993-977

R_{15} = 16

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Answer:

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= $0.10 + $0.10           [$0.10 is lesser than $0.30]

= $0.20

Third day fine = $0.20 + $0.20           [ $0.20 is lesser than $0.30]

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Therefore, the total fine for a book on the fourth day is $0.70

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