All categories

3 years ago

B - 1/4 = 3 1/2 please help I need to correct my answer

Mathematics

1 answer:

Nutka1998 [239]3 years ago

7 0

Answer:

b= fifteen over four

Step-by-step explanation:

b= 1/4 + 3 1/2

You might be interested in

Write the slope-intercept form of the equation for the line

olga_2 [115]

Answer: y=-3/10x+1/2

Step-by-step explanation:

3 0

3 years ago

Right triangle XYZ is shown. Y (2,6) (1, 2) 6 х 7 Z Rounded to the nearest hundredth of a unit, what is the length of the hypote

Dmitriy789 [7]

Answer:

8.12

Step-by-step explanation:

We obtain the distance between x and y

d = sqrt[(x2 - x1)² + (y2 - y1)²]

d = sqrt[(1 - 2)² + (2 - 6)²]

d = sqrt[1 + 16)

d = sqrt(17)

d² = 17

From Pythagoras rule;

Hypotenus = sqrt(Adjacent² + opposite²)

Hence,

Hypotenus = sqrt(17 + 7²)

Hypotenus = sqrt(17+ 49)

Hypotenus = sqrt(66)

Hypotenus = 8.124

Hypotenus = 8.12

7 0

3 years ago

for points A, B, and C, AB = 2, BC = 3, and AC = 4. Select one: a. A, B, and C are noncollinear. b. A, B, and C form a right tri

victus00 [196]

Short Answer: A
Remark
C
Let's start with the false choices.
If they were colinear, then if AB + BC would = 5 or 1 depending on the location of C. Answer C is not correct.

B
a b and c do not form a right triangle. a^2 + b^2 ≠ c^2
2^2 + 3^2 = 13 not 16 (which is what c^2 or 4^2 = )

D
D is false. Equilateral triangles have 3 equal sides.

A is true. Since A and C are opposites and you have eliminated C by arguing A. Then A must be the answer.

3 0

4 years ago

Please help.. I'm really stuck

sertanlavr [38]

Answer:

C. C only

Step-by-step explanation:

Well to determine if the given graphs are functions we need to do the vertical line test to all the graphs,

A. This fails the vertical line test because the vertical line could pass through 2 points on the lines.

B. this also fails because a vertical line could pass through 2 points.

C. This passes because the vertical line doesn’t touch 2 points.

6 0

3 years ago

Solve and write in interval notation. 4|x+4|+5>5

velikii [3]

Hi,

Solving:

$4 |x + 4| + \not5 > \not5 \\ 4 |x + 4| > 0 \\ 4 |x + 4| = 0 \: \: \: \: \: | \div 4 \\ |x + 4| = 0 \\ x + 4 = 0 \\ x = - 4 \\ x \in \: r \: \: \: \: \: ( - 4)$

Answer: The inequality is true for any value of x, except when X = -4

Hope this helps.
r3t40

8 0

3 years ago

Read 2 more answers