codes for a specific trait
I hope this help and I will try again if it is wrong.
Answer:
After constructing a prototype of the device, the student concludes that in many regions the monetary cost of building and installing the device would be higher than the cost of acquiring water from other sources. Which of the following would be most appropriate for the student to do next?
redesign the device without the solar panel so that it plugs into an electrical outlet
Explanation:
Because of cost implication, the device is redesigned in order to use other source rather than water which would be cost-effective and generally accepted for use.
Answer:
Because the English measurement system has been in use for a very long time, it will be costly and time consuming to change from the English to SI units. Many technological measurements, products, and tools were developed in English units.
The cost of converting all measurements to SI units will be costly and will require a long period of time. Conversions between the English and the SI system of units appear to be more cost-effective than hardware changes.
Example:
It will be costly to convert designs for bridges, tunnels, locomotives, automobiles, and other hardware to the SI system. Although new designs are being performed in SI units, much useful hardware based on English units still remain.
Eventually, it is likely that complete conversion from English to SI units will happen, albeit slowly.
<span> Biotic components or biotic factors are any living organisms that affect another
organism. These components shape an ecosystem which includes animals that
consume organisms in question and its living food that the said organisms
consume. Biotic components include human influence. Producers, consumers and
decomposers usually comprise biotic components.</span>
<span> </span>
For this, you need to use Punnett squares.
You know the genotype of the parents, and for the cross, you need to separate into two alleles, both genes.
AABBCc divided like ABC and ABc.
Aabbcc divided like Abc and abc.
Now you can cross them, and all probabilities will be:
AABbCc, AaBbCc, AABbcc and AaBbcc
So, you could say 25% of the offspring will be AaBbCc, 25% AaBbcc, 25% AABbCc, and 25% AABbcc
