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Anon25 [30]
3 years ago
10

12/15 in simplest form

Mathematics
2 answers:
alex41 [277]3 years ago
3 0
\frac{12}{15} in simplest form:

First, find the greatest common factor (GCF) of 12, 15. 
Factors of 12: 1, 2, 3, 4, 6, 12
Factors of 15: 1, 3, 5, 15
The GCF is 3. 
Second, divide the numerator (12) by the GCF. / Your problem should look like: 12 ÷ 3 = 4
Third, divide the denominator (15) by the GCF. / Your problem should look like: 15 ÷ 3 = 5
Fourth, rewrite the fraction in the simplified form. / Your problem should look like: \frac{4}{5}

Answer: \frac{4}{5}

nexus9112 [7]3 years ago
3 0

Answer:

First, find the greatest common factor (GCF) of 12, 15. 

Factors of 12: 1, 2, 3, 4, 6, 12

Factors of 15: 1, 3, 5, 15

The GCF is 3. 

Second, divide the numerator (12) by the GCF. / Your problem should look like: 12 ÷ 3 = 4

Third, divide the denominator (15) by the GCF. / Your problem should look like: 15 ÷ 3 = 5

Fourth, rewrite the fraction in the simplified form. / Your problem should look like: 

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Lapatulllka [165]

Answer:

Formula for mean in grouped data

= Zfx/ Zf

f = sum of the number of mice

= 35

Frequency = 39 + x

Mean = 7

Fx = 20 + 78 + 112 + 8x + 54

= 264 + 8x

7 = 264 + 8x/ 39 + x

7(39+x) = 264 + 8x

After solving you will get

x = 9

Hope this helps.

4 0
3 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
Solve the equations if possible <br><br> * -5×=×+6(1-×)<br><br> *(2×-5)²=(2×-1)(2×+1)-10(2×-1)
Allushta [10]
-5x = x + 6(1-x)

-5x = x + 6(1) + 6(-x)
-5x = x + 6 -6x
-5x = x - 6x + 6
-5x = -5x + 6
-5x + 5x = 6
0 = 6  Not equal. No solution.

(2x-5)² = (2x-1)(2x+1) -10(2x-1)
(2x-5)(2x-5) = (2x-1)(2x+1) - 20x + 10
2x(2x-5)-5(2x-5) = 2x(2x+1)-1(2x+1) - 20x + 10
4x² - 10x -10x + 25 = 4x² + 2x - 2x -1 - 20x + 10
4x² - 20x + 25 = 4x² - 20x - 1 + 10
4x² - 20x + 25 = 4x² - 20x - 9

Not equal. No solution.

8 0
3 years ago
Solve for b.<br><br> b + -78 = 10
love history [14]
The answer is b=88

Hope this helped!

3 0
3 years ago
Vector v has a direction of (5,3) find the direction angle for v to the nearest degree
Vesnalui [34]

Answer:

31^{\circ}

Step-by-step explanation:

We have been given that vector v has a direction of (5,3). We are asked to find direction angle for v to nearest degree.

We know that direction of vector with components (a,b) can be determined by \theta=\text{tan}^{-1}(\frac{b}{a}).

Upon substituting the components of given vector in above formula, we will get:

\theta=\text{tan}^{-1}(\frac{3}{5})

\theta=30.9637565^{\circ}

Upon rounding to nearest degree, we will get:

\theta\approx 31^{\circ}

Therefore, the direction angle for vector v is 31 degrees.

3 0
3 years ago
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