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damaskus [11]
2 years ago
10

Are the equation linear or nonlinear?​

Mathematics
1 answer:
I am Lyosha [343]2 years ago
8 0

Answer:

<em>Results below</em>

Step-by-step explanation:

<u>Equation of the line</u>

A straight line can be written in the form:

y = ax + b

Where a and b are constants and x is the independent variable.

The essential condition for an equation to be linear is that the x must be powered to the exponent 1, which is usually not written.

From the equations presented in the table:

y = x^1+2 is linear because the exponent of the x is 1

y = 5(x+2) = 5x + 10 is linear with a=5 and b=10.

y = x is linear with a=1 and b=0

y = x^2+1 is not linear because the exponent of x is 2

y = x(x) = x^2 is not linear because the exponent of x is 2

The table below summarizes the results

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What is 13.62 divided by -3.14?
Alex Ar [27]

Answer:

-4.3375796178343949044585987261146‬

Step-by-step explanation:

you can probably round it off but that is what my calculator gave me.

4 0
3 years ago
Which system of equations is represented by the graph?
Tom [10]

Answer:

C

Step-by-step explanation:

y=x is a line that has slope 1 meaning it go ups (increases) from left to right.

So that puts us at choice A or C.

Both A or C differ by the numerator for the other function.

We can find the x-intercept for A and C by setting the numerator equal to 0 and solving for x.

Let's do that:

A:  -x-10=0                           C.  -x+10=0

     -x=10                                    -x=-10

      x=-10                                    x=10

A says x-intercept -10

C says x-intercept 10

Your graph intercepts the x-axis at 10 so the answer is C.

4 0
3 years ago
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Compound interest earns interest on both the principal and the interest already earned.
kow [346]

Answer:

Step-by-step explanation:

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5 0
3 years ago
Given: AB = 4 AC = 6 What point is in the interior of both circles? H. A. B.
AleksAgata [21]

Answer:

Point A is in the interior of both circles

Step-by-step explanation:

<u><em>Verify each point</em></u>

we know that

Point H is in the interior of greater circle but is outside smaller circle

Point A is the center both circles, then is in the interior of greater circle and is in the interior of smaller circle

Point B is on the smaller circle and is in the interior of greater circle

therefore

Point A is in the interior of both circles

5 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
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