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vovangra [49]
3 years ago
12

The angles of a quadrilateral measure 80, 100, 100 and 80 in the order. what kind of quadrilateral has this shape? How do you no

w?
Mathematics
1 answer:
Tanya [424]3 years ago
8 0
This quadrilateral would be a trapezoid. You have two obtuse angels next to each other, followed by two acute angels next to each other, in this case it's simply a matter of taking a pencil and drawing it out.
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C) A researcher has extracted two samples from the same target population, sample A and sample B. Sample A has a mean of 25 kg w
aleksandrvk [35]

Answer:

dsgberhyujxgkloyjnhbgfvbhnjklkjhbgfdfghjkiopolkjhgfew

Step-by-step explanation:

3 0
3 years ago
Allison and Megan were at track practice. The track is 3/8 kilometers around.
Ad libitum [116K]

Allison ran 3/8 km (0.375 km) in 3 minutes.

Set up a proportion to find how long it takes for her to run 1 km

\frac{0.375\textrm{km}}{3 \textrm{min}} = \frac{1\textrm{km}}{x \textrm{min}}

Cross multiply to get:

3 = 0.375x

Solve:

x = \frac{3}{0.375}

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5 0
3 years ago
Pls helpppppp this is a math emergency!
netineya [11]

Answer:

19.4in

Step-by-step explanation:

1) formula for area of a triangle:

(b*h)/2=a

the area and height are already given so lets substitute them in the formula.

(b*23.8)/2=230.86

1) multiply by 2 on both sides

b*23.8=461.72

divide by 23.8 on both sides

b=19.4

the base is 19.4 in

hope this helps

3 0
3 years ago
Read 2 more answers
A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student
umka2103 [35]

Answer:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X_{M}= 69.8 represent the mean for the age of grandmother

\bar X_{F}= 71.6 represent the mean for the age of grandfather

s_{M}= 8.38 represent the sample deviation for the age of grandmother

s_{F}= 6.65 represent the sample deviation for the age of grandfather

n_M = n_F= 10

Solution to the problem

For this case the confidence interval is given by:

(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n_M +n_F-2=10+10-2=18

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that t_{\alpha/2}=2.101

And replacing we got:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

5 0
3 years ago
Solve.
timofeeve [1]
M = 14 3/5 is the answer
4 0
3 years ago
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