For any arbitrary 2x2 matrices

and

, only one choice of

exists to satisfy

, which is the identity matrix.
There is no other matrix that would work unless we place some more restrictions on

. One such restriction would be to ensure that

is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking

we'd get equality.
Answer:
NQ = 26 cm
Step-by-step explanation:
A line bisector divides a line into two equal segments.
Given that line l is the bisector of segment NQ, it then means it divides NQ into two equal segments, namely, segment NP and segment PQ.
Thus, NP = ½ of segment NQ
Therefore, if NP = 13 cm,
13 = ½*NQ
multiply both sides by 2
2*13 = NQ
26 = NQ
NQ = 26 cm
Do you have any options to pick from
Answer:
A. $105
Step-by-step explanation:
Given
total charge= $700 per concert
<u>solution</u>
If Fredrick receives $175 of that money, the balance will be
$700-$175= $525
The balance will be shared by the 5 members
<em>Hence each of them will take</em>
525/5=$105
<span>A. Find the complement of the angle shown
90 - 52 = 38
</span><span>B. Find the supplement of the angle shown.
180 - 52 = 128
hope that helps</span>