3 years ago

What is the base of the exponential expression of 4 to the power of 5

Mathematics

1 answer:

artcher [175]3 years ago

4 0

That’s a hard question

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Use substitution to solve s+a=4 and 35+5a=2550

mario62 [17]

35+5(4-s)=2550
35+20-5s=2550
55-5s=2550
-55 -55
-5s = 2495
s = - 499

-499 + a = 4
+499 +499
a = 503

5 0

3 years ago

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1• (a + 3) = a + 3<br> What is the property

Artist 52 [7]

Answer:

the commutative property because you’re not changing the way its form style, but of more like their former

6 0

2 years ago

Plz help, Lots of points

Ierofanga [76]

Answer:

1. 141.3

2. 23.14

3. 31.4

3 0

2 years ago

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Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin

icang [17]

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

$\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}$

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

$y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}$

$y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}$

$y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}$

It is linear differential equation because this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

$y'+P(x)y=g(x)$

$P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}$

$\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}$

Homogeneous equation

$\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}$

Degree of f and g are same.

$f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x$

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

3 0

3 years ago

Marion is 3 years more than 5 times as old as Paula. if p represents Paula's age, which expression represents Marion's age?

Alborosie

5p + 3

because its 5 times Paula's age with the additional 3 years tacked on to it

8 0

2 years ago

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