Yeah where is the questions?
Answer:
59.2 m
Step-by-step explanation:
The tangent of the angle of elevation will be the ratio of pole height to distance from the pole:
tan(2α) = h/10
tan(α) = h/70
The double-angle formula for tangents tells us ...
tan(2α) = 2tan(α)/(1 -tan(α)²)
Multiplying by the denominator and substituting from above, we get ...
(1 -(h/70)²)(h/10) = 2(h/70)
7(1 -(h/70)²) = 2 . . . . . . . . multiply by 70/h
1 - 2/7 = (h/70)² . . . . . . . . divide by 7, subtract 2/7-(h/70)²; next: square root
h = 70√(5/7) ≈ 59.2 . . . . meters
The height of the top of the pole is about 59.2 meters above the observer.
Answer:
speed=225.75 miles per hour
Step-by-step explanation:
given:
s=301/2
t=2/3
we have,
v=s/t
v=(301/2)/(2/3)
=(301/2)×3/2
=903/4
v=225.75
therefore, speed of car will be 225.75 miles per hour