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3 years ago

Solve the equation x+12+2x=20+3x−8.

Mathematics

1 answer:

LenaWriter [7]3 years ago

3 0

Answer:

Infinitely many.

Step-by-step explanation:

Combine like terms as shown below

x + 12 + 2x = 20 + 3x - 8

Side one

x + 2x = 3x

Side two

20 - 8 = 12

Set the equation up again

3x + 12 = 3x + 12

The equation is the same on both sides which means that the equation cancels itself out.

3x - 3x = 0 and 12 - 12 = 0

0 = 0 so there is infinitely many solutions because both sides equal the same thing.

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The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in 4th quadrant so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

3 years ago

I literally have no clue what this unit is about so help

vaieri [72.5K]

The answer is D
if the legs are 5 and 4 cm the equation to find the hypotenuse would be 5^2+4^2=c^c
5 squared is 25 and 4 squared is 16 that gives you 41, normally you would square root the 41 but it gives you a decimal number

5 0

3 years ago

Read 2 more answers

What is the solution to the systems of equations? y= 2/3x + 3 x=-2

Romashka [77]

Answer:

y = 8/3

Step-by-step explanation:

x = -2

y = 2/(3*-2) + 3

y = 2/-6 + 3

y = -1/3 + 3