Answer:
[-4/5]×3/7×15/16×[-14/9]= 1/2
Step-by-step explanation:
hope this helps :)
Answer:
c
Step-by-step explanation:
Answer:
No, the Roger’s claim is not correct.
Step-by-step explanation:
We are given that Roger claims that the two statistics most likely to change greatly when an outlier is added to a small data set are the mean and the median.
This statement by Roger is incorrect because the median is unaffected by the outlier value and only the mean value gets affected by the outlier value.
As the median represents the middlemost value of our dataset, so any value which is an outlier will be either at the start or at the end will not the median value. So, the median will not likely change when an outlier is added to a small data set.
Now, the mean is the average of all the data set values, that is the sum of all the observations divided by the number of observations. The mean will get affected by the outlier value because it take into account each and every value of the data set.
Hence, the mean will likely to change greatly when an outlier is added to a small data set.
Answer:
- 1
Step-by-step explanation:
Using the order of operations PEMDAS ( parenthesis, exponents, multiplication, division, addition, subtraction )
Given
17 - 6 × 10 ÷ 2 + 12 ← perform multiplication
= 17 - 60 ÷ 2 + 12 ← perform division
= 17 - 30 + 12 ← perform addition/ subtraction from left to right
= - 13 + 12
= - 1
Let us examine the speed of growth of the function. We have that the difference between successive terms is: 2, 4, 8, 16. These are powers of 2 and thus there is clearly an exponential increase in the parent function. In fact, the function can be modeled by f(x)=C+2^x where C is a constant.
We have that the new function is g(x). Translating upwards by 5 means that the new y-values are 5 units higher. Hence, we have that the pairs (x,f(x)) correspond to the pairs (x,f(x)+5) and thus the answer is that the f(x)/y-values will be increased by 5.
According to the above, we need to check the given values and see whether in some cases we have g(x)=f(x)+5; in layman's terms, we need to check whether for some x, the new y-value is bigger by 5 from the old one. This is the case only for (2,16) since the old point was (2,11).
