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GenaCL600 [577]
3 years ago
5

Draw a number line from –10 to 10. Put tick marks at each integer. Graph a point with the given coordinate.

Mathematics
1 answer:
Doss [256]3 years ago
4 0
Lets try to draw a line here, now, I can draw the tick marks but you can imagine them that there are above the numbers 

__________F________________________________________________
-10  -9  -8  <u><em>-7</em></u>  -6  -5  -4  -3  -2  -1  0  1  2  3  4  5  6  7  8  9  1 0

the answer is C

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Answer:

y = 2x - 1

Step-by-step explanation:

In an equation with the form y = mx + b, the slope is m. Because parallel lines have the same slope, the slope of the other line is also 2. Plug this back into the mx + b form to get y = 2x - 1.

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A(1)= -13 <br><br> a(n)= a(n-1)+4 <br><br> Find the 2nd term in the sequence
eimsori [14]

The second term of the arithmetic sequence is:

a₂= -9

<h3>How to find the second term in the sequence?</h3>

Here we have an arithmetic sequence, such the the recursive formula is:

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So to get each term, we need to add 4 to the previous one.

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a₁ = -13

Then the second term will be:

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7 0
1 year ago
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6 0
2 years ago
What is the equation of the circle with center (-6,7) that passes through the point (4,-2). A. (x+6)^2+(y-7)^2=181 B. (x-6)^2+(y
pychu [463]
The equation of a cricle passing through (h,h) and with radius r is
(x-h)^2+(y-k)^2=r^2
so

cente ris (-6,7) and passing through (4,-2)
(x-(-6))^2+(y-7)^2=r^2
(x+6)^2+(y-7)^2=r^2
subsitute (4,-2) to find r^2

(4+6)^2+(-2-7)^2=r^2
(10)^2+(-9)^2=r^2
100+81=r^2
181=r^2

so it is

(x+6)^2+(y-7)^2=181
A is the answer
3 0
3 years ago
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