The three angles of a triangle are in the ratio 3:3:4. What information can you give about the triangle?

2 answers:

7 0

The information tells us that this triangle is an isosceles triangle meaning two sides and two angles are congruent. Also, this is not a right triangle as the only isosceles right triangle has a ratio of 1:1:2

Hope this helps!

Vera_Pavlovna [14]3 years ago

4 0

Let the angles be x.
3x + 4x + 4x = 180 (angle sum property of a triangle is 180 degrees.)
12x = 180
x = 180/12
x= 15
the angles are 45, 60 and 60
it is an isosceles triangle.

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Answer:

Step-by-step explanation:

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Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$