What conclusion can you make about you negative number raised to an odd power

When u don’t wanna get off ur couch...

prohojiy [21]

Answer:

huh?

Step-by-step explanation:

7 0

3 years ago

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What is the simplified form of the following expression? Assume a greater-than-or-equal-to 0 and c greater-than-or-equal-to 0

Setler [38]

Answer:

A. 7ac(^4sqrt. ab^2)

Step-by-step explanation:

just took the quiz on edg.

3 0

3 years ago

A pyramid has a square base of length 8cm and a total surface area of 144cm². Find the volume of the pyramid. (Please use Pythag

Sveta_85 [38]

Answer:

$\displaystyle V_{ \text{pyramid}}= 64 \: {cm}^{3}$

Step-by-step explanation:

we are given surface area and the length of the square base

we want to figure out the Volume

to do so

we need to figure out slant length first

recall the formula of surface area

$\displaystyle A_{\text{surface}}=B+\dfrac{1}{2}\times P \times s$

where B stands for Base area

and P for Base Parimeter

so

$\sf\displaystyle \: 144=(8 \times 8)+\dfrac{1}{2}\times (8 \times 4) \times s$

now we need our algebraic skills to figure out s

simplify parentheses:

$\sf\displaystyle \: 64+\dfrac{1}{2}\times32\times s = 144$

reduce fraction:

$\sf\displaystyle \: 64+\dfrac{1}{ \cancel{ \: 2}}\times \cancel{32} \: ^{16} \times s = 144 \\ 64 + 16 \times s = 144$

simplify multiplication:

$\displaystyle \: 16s + 64 = 144$

cancel 64 from both sides;

$\displaystyle \: 16s = 80$

divide both sides by 16:

$\displaystyle \: \therefore \: s = 5$

now we'll use Pythagoras theorem to figure out height

according to the theorem

$\displaystyle \: {h}^{2} + (\frac{l}{2} {)}^{2} = {s}^{2}$

substitute the value of l and s:

$\displaystyle \: {h}^{2} + (\frac{8}{2} {)}^{2} = {5}^{2}$

simplify parentheses:

$\displaystyle \: {h}^{2} + (4 {)}^{2} = {5}^{2}$

simplify squares:

$\displaystyle \: {h}^{2} + 16 = 25$

cancel 16 from both sides:

$\displaystyle \: {h}^{2} = 9$

square root both sides:

$\displaystyle \: \therefore \: {h}^{} = 3$

recall the formula of a square pyramid

$\displaystyle V_{pyramid}=\dfrac{1}{3}\times A\times h$

where A stands for Base area (l²)

substitute the value of h and l:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times \{8 \times 8 \}\times 3$

simplify multiplication:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times 64\times 3$

reduce fraction:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{ \cancel{ 3 \: }}\times 64\times \cancel{ \: 3}$

hence,

$\sf\displaystyle V_{ \text{pyramid}}= 64 \: {cm}^{3}$

8 0

3 years ago

What is the area of the parallelogram with a base of 1.75 cm and a height of 1.5 cm? 2.75 cm2 3.625 cm2 2.625 cm2 3.25 cm2

choli [55]

Answer:

Step-by-step explanation:

Area of parallelogram=base*height

So 1.75*1.5=2.625cm²

8 0

3 years ago

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A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i

Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

$W=\frac{1}{2}kx^2$

where k= spring constant

x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

$W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k$

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

$W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k$

4 0

3 years ago