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mylen [45]
3 years ago
7

Find the slope of the line graphed in the diagram and choose the correct answer from the choices below. The two intercepts are (

0,3) and (-2.5,0)

Mathematics
1 answer:
balandron [24]3 years ago
3 0

Answer:

6/5

Step-by-step explanation:

Using the given points (0, 3) and (-2.5, 0) you can substitute it into the slope formula which is y2-y1/x2-x1

In this case, 3 in the first parenthesis is the y2, while 0 in the second parenthesis set is 0.

so,

= substitute in the numbers for the slope formula: 3-0/0-(-2.5)

= reduce the fraction and you get: 1.2

= convert to simplified fraction to get: 6/5

Hope this helps, I did this on a quiz and got the answer right.

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HELP!!!! Choose the correct answer. Which expression, when evaluated,
blagie [28]

We will check each options and verify it

(a)

18-2m

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(b)

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Ava buys a book for 8.58. She pays with a $10 bill. How much charge will she get
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Read 2 more answers
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
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