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Anton [14]
3 years ago
15

Which situation can be modeled by the equation y=3x+25

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0

For this case we have the following situation:

The monthly cost of a gym in the city is $ 3. The initial registration is $ 25. Write a mathematical expression that models the problem.

So we have to define variables:

x: number of months

y: total cost

The mathematical expression that models the problem is:

y = 3x + 25

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What point is 2/3 of the distance from point A(3, 1) to point B(3, 19)?
8_murik_8 [283]

Answer: (3, 13)

Step-by-step explanation:

If we let the point be P, then AP:BP=2:1.

P=\left(\frac{(2)(3)+(1)(3)}{2+1}, \frac{(2)(19)+(1)(1)}{2+1} \right)=(3, 13)

5 0
2 years ago
For her exercise today, Keiko plans to both run and swim. Let r be the number of laps she runs and let s be the number of laps s
DerKrebs [107]

Answer:

5r + 3s ≥ 30

Step-by-step explanation:

We know Keiko wants to do exercise at least 30 minutes a day, and she wants ideally to mix up the activities, by combining running and swimming into her schedule.

Since each lap she runs takes 5 minutes and each lap she swims takes 3 minutes, these will be the left side of the inequality:

5r + 3s

She wants to exercise at least 30 minutes a day, so...

5r + 3s ≥ 30

she could do 3 laps of running and 5 laps of swimming for example.

6 0
3 years ago
Consider the equation y = –3(x – 3) Which equation, when graphed with the given equation, will form a system with lines that ove
pentagon [3]

Answer:

y=-3x+9 (D)

Step-by-step explanation:

8 0
3 years ago
In science class the girl to boy ratio is 6 to 2. If there are 30 girls how many boys are there?
schepotkina [342]

Answer:

10 boys

Step-by-step explanation:

6:2 simplfies to 3:1 30 / 3 = 10

30:10 simplfies down to 6:2

8 0
4 years ago
Read 2 more answers
Write 3x^2-18x-6 in vertex form
Vedmedyk [2.9K]
The standard form of a quadratic equation is \displaystyle{ y=ax^2+bx+c, while the vertex form is:

                      y=a(x-h)^2+k, where (h, k) is the vertex of the parabola.

What we want is to write \displaystyle{ y=3x^2-18x-6 as y=a(x-h)^2+k

First, we note that all the three terms have a factor of 3, so we factorize it and write:

\displaystyle{ y=3(x^2-6x-2).


Second, we notice that x^2-6x are the terms produced by (x-3)^2=x^2-6x+9, without the 9. So we can write:

x^2-6x=(x-3)^2-9, and substituting in \displaystyle{ y=3(x^2-6x-2) we have:

\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11].

Finally, distributing 3 over the two terms in the brackets we have:

y=3[x-3]^2-33.


Answer: y=3(x-3)^2-33
6 0
4 years ago
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