26 points A stoplight has the following cycle: green for 25 seconds, yellow for 4 seconds, and red for 2 minutes. What is the pr
obability that the light will be green when you arrive to the nearest hundredth?
0.17
0.03
0.83
0.81
2 answers:
Answer:
0.17
Step-by-step explanation:
Time for green = 25 sec
Time for yellow = 4 sec
Time for red = 2 x 60 sec = 120 sec
Total time = 149
Probability of getting green = (time of green)/ (total time)
= 25/149
=0.169
Approximately = 0.17
Answer:
25+4+120(2min) = 149
25/149 = 0.16778523489932885906040268456376
= (rounded) 0.17
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