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sergey [27]
4 years ago
11

26 points A stoplight has the following cycle: green for 25 seconds, yellow for 4 seconds, and red for 2 minutes. What is the pr

obability that the light will be green when you arrive to the nearest hundredth?
0.17
0.03
0.83
0.81
Mathematics
2 answers:
Zarrin [17]4 years ago
4 0

Answer:

0.17

Step-by-step explanation:

Time for green = 25 sec

Time for yellow = 4 sec

Time for red = 2 x 60 sec = 120 sec

Total time = 149

Probability of getting green = (time of green)/ (total time)

= 25/149

=0.169

Approximately = 0.17

Anika [276]4 years ago
3 0

Answer:

25+4+120(2min) = 149

25/149 = 0.16778523489932885906040268456376

= (rounded) 0.17

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We get that the value of x is option (b) 70.

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Answer:

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Step-by-step explanation:

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