Answer:

Step-by-step explanation:
In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.
Evaluating the integral gives use that it is equal to;

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.
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It is prime because it has no common factors in 5a^2 and b.
The answer is
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Answer:
Equation with variable
Step-by-step explanation:
Has to be B other I don't know
So you you are trying to find the area of sphere so you would use this formula
A=4•3.14•r^2
And you already know that the radius is 6 so you would go ahead and plug in the numbers
A=4•3.14•4^2
4^2 is 16 so your final equation would be
A=4•3.14•16
And your answer is
=452.39