Question

WILL GIVE BRAINLIEST! Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the origin and (−3, 4).

Answer 1

Answer:

$(\frac{17}{18}, \frac{23}{6})$

Step-by-step explanation:

D1 = $\sqrt{(x+3)^2 + (y-4)^2}$

D2 = $\sqrt{x^2 + y^2}$

Then set D1 = D2, and substitute in y = 3x+1

$\sqrt{(x+3)^2 + (3x-3)^2}$ = $\sqrt{x^2 + (3x+1)^2}$

$x^2 +6x +9 +9x^2 - 18x + 9 = x^2 + 9x^2 + 6x + 1$

$18x = 17$

x = 17/18

Then to find y, substitute back in x for y = 3x + 1

$y = \frac{17}{18} * 3 + 1$

y = 23/6

Answer 2

Answer:

I hope this helps you :)

If this doesn't help I can try and resolve the equation to get your best answer

Step-by-step explanation: