In both problems, the sum of side lengths is the perimeter. Opposite sides of a parallelogram (or rectangle) are equal in length, so you can find the perimeter by doubling the sum of adjacent sides.
25. 2(x +(x +15)) = (x +45) +(x +40) +(x +25)
.. 4x +30 = 3x +110 . . . . . . . . . . . . . . . . . . . . . . simplify
.. x = 80 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . subtract 3x+30
.. 4x +30 = 4*80 +30 = 240
The perimeter of each is 240 units.
26. 2(x +(x +2)) = (x) +(x +6) +(x +4)
.. 4x +4 = 3x +10 . . . . . . . . . . . . . . . . . . . . . . simplify
.. x = 6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . subtract 3x+4
.. 4x +4 = 4*6 +4 = 28
The perimeter of each is 28 units.
Answer:
total distance might be 16
Step-by-step explanation:
|y2-y1/x2-x1|, plug it the numbers, if you got a negative number, its just positive since the equation is set to absolute value
Answer:
4 possible ways this could happen
Step-by-step explanation:
1. $11
2. $12
3. $13
4. $14
hope this was helpful
We have that
<span> -3r+3u
</span>
Step 1
<span>Use the distance formula to find the radius
</span><span>r = √(x^2 + y^2)
(x,y)----------> (</span>-3,3)
r= √(-3^2 + 3^2)=√18=3√2
Step 2
Use the tangent to find the angle
θ = arctan(y/x)
θ = arcTan(3/-3)= -45°-------> II Quadrant
then
θ=180-45=135°
Step 3
write in polar form
(x,y)------------> (r, θ)
so
(-3,3)----------> (3√2, 135°)
the answer is (3√2, 135°)
b = 78°
The angles at a point sum to 360°
that is 45 + 237 + b = 360
282 + b = 360 ( subtract 282 from both sides )
b = 360 - 282 = 78°
