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2 years ago

Can you please help me find the answer to this algebraic equation~ 5(v–5)=10

Mathematics

1 answer:

joja [24]2 years ago

6 0

5(v-5)=10.
5v-25=10
5v=35
v=7

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A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)

stiks02 [169]

Answer: 82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB $=\sqrt{(9+1)^2+(-1-7)^2}$ units [By distance formula : $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ ]

$=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41}$ units

Width = BC = $\sqrt{(-1+5)^2+(7-2)^2}$ units

$=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}$

Area = length x width

= $2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}$

Hence, the area of the rectangle is 82 sq. units .

7 0

2 years ago

Please answer quickly, thank you for your help

RoseWind [281]

Answer:

-6<x<-9

Step-by-step explanation:

if x+9<0 and 2x>-12

x<-9

x>-6

X is smaller than -9 but greater than -6.

The solution is -6<x<-9

6 0

2 years ago

Read 2 more answers

If the probabilities that an automobile mechanic will service 3, 4, 5, 6, 7, or 8 or more cars on any given workday are, respect

Readme [11.4K]

Answer:

$P(X\geq 5)=0.69$

Step-by-step explanation:

We need to find the probability that the mechanic will service or more cars.

It's a simpler one given that we have the probabilities of servicing 4 or less cars.

P(at least 5 cars) is given by subtracting the probabilities of servicing both 3 and 4 cars.

$P(X\geq 5)=1-p(x=4)-p(x=3)\\P(X\geq5)=1-0.12-0.19\\P(X\geq5)=1-0.31\\=0.69$

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2 years ago

What is the equation of the line x–3y=18 in slope-intercept form? Drag and drop the appropriate number, symbol, or variable to e

Sunny_sXe [5.5K]

Simple...

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You want to convert it into slope-intercept form or y=mx+b form-->>>

x-3y=18

Isolate the variable-->>

x-3y=18
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Now simply divide...

$\frac{-3y}{-3} = \frac{-x+18}{-3}$

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Thus, your answer.