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MrRissso [65]
3 years ago
12

I need help please! I need to know what is/how to get a,b, and c for factoring trinomials of the problem (x-3)(x+4)=0.

Mathematics
1 answer:
Readme [11.4K]3 years ago
6 0

Answer: Trinomials often (but not always!) have the form x2 + bx + c. ... So, how do you get from 6x2 + 2x – 20 to (2x + 4)(3x −5)? Let's take a look. Factoring Trinomials

Step-by-step explanation:

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Calcium-41 is being used in studies testing the effectiveness of drugs for preventing osteoporosis. The half-life of calcium-41
Leviafan [203]

Answer:

332,193 years

Step-by-step explanation:

From the question above, we are to calculate the time in an half life question, hence, the formula is given as

t = In(Nt/No) ÷ -(In2/t½)

Where

t = time is takes for an substance to decay or reduce

Nt = Amount of sample after time = 2g

No = Initial amount of sample = 20g

t½ = Half life = 100,000 years

Hence,

t = In(2/20) ÷ (In 2/ 100,000)

t = 332192.80948874 years

Approximately = 332,193 years

7 0
3 years ago
Finding values or<br> k(x) = x - 2<br> h(x) = x2 +1<br> (h + k)(2) =
Serjik [45]

Answer:

<h2>(h + k)(2) = 5</h2>

Step-by-step explanation:

(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5

\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5

5 0
2 years ago
Convert (-6, -6) from Cartesian coordinates to polar coordinates. Round the length to the nearest 0.01 Express the
Neko [114]

9514 1404 393

Answer:

  (8.49; 225°)

Step-by-step explanation:

The angle is a 3rd-quadrant angle. The reference angle will be ...

  arctan(-6/-6) = 45°

In the 3rd quadrant, the angle is 45° +180° = 225°.

The magnitude of the vector to the point is its distance from the origin:

  √((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49

The polar coordinates can be written as (8.49; 225°).

_____

<em>Additional comment</em>

My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.

3 0
2 years ago
Factorise the following algebraic expressions completely a. y4 −81 . x2 +10x +24
Ludmilka [50]

y^4-81=(y^2-9)(y^2+9)=(y-3)(y+3)(y^2+9)\\\\&#10;x^2 +10x +24 =x^2+10x+25-1=(x+5)^2-1=(x+5-1)(x+5+1)=(x+4)(x+6)

3 0
3 years ago
Tyler ate x fruit snacks, and Han ate 3/4 less that. write an expression for the number of fruit snacks Han ate​
Alika [10]

x = ×-3/4

because you hace the variable x and you do not know the number of fruit snacks he ate and you need to have the same variables to properly find the answer.

3 0
2 years ago
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