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3 years ago

I need help please! I need to know what is/how to get a,b, and c for factoring trinomials of the problem (x-3)(x+4)=0.

1 answer:

6 0

Answer: Trinomials often (but not always!) have the form x2 + bx + c. ... So, how do you get from 6x2 + 2x – 20 to (2x + 4)(3x −5)? Let's take a look. Factoring Trinomials

Step-by-step explanation:

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Which statement best describes the relationship between x and y in the equation y = 3x? A. The value of y is three less than the

7nadin3 [17]

Answer:

Step-by-step explanation:

Y is three times the value of x , It can be said that y is directly proportional to Y .

Direct proportion is when an increase in the independent variable causes an increase in the dependent variable.

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2 years ago

The diameter of a circle is 15 in. Which measure below cannot be a chord on the same circle?

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It's c 18, because the diameter is the longest chord so it would be greater than 15.

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3 years ago

What are the values of the variables in the triangle below? If your answer is not an integer, leave it in simplest radical form.

castortr0y [4]

Answer:

Step-by-step explanation:

<u>To find x we use cosine</u>

cos∅ = adjacent / hypotenuse

x is the adjacent

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x = 8√3 cos 30

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Hope this helps you

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2 years ago

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2 years ago

The American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day. Legacy

inessss [21]

Answer:

We conclude that the null hypothesis is rejected which means residents of Legacy Ranch use less water on average.

Step-by-step explanation:

We are given that the American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day.

Twenty-three owners responded, and the sample mean water use per day was 63 gallons with a standard deviation of 8.1 gallons per day.

<u><em>Let </em></u> $\mu$ <u><em> = average water usage by residents of Legacy Ranch.</em></u>

So, Null Hypothesis, $H_0$ : $\mu \geq$ 67 gallons {means that the residents of Legacy Ranch uses more or equal to 67 gallons water on average}

Alternate Hypothesis, $H_A$ : $\mu$ < 67 gallons {means that the residents of Legacy Ranch use less water on average}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean water use per day = 63 gallons

s = sample standard deviation = 8.1 gallons

n = sample of responded = 23

So, <u><em>test statistics</em></u> = $\frac{63-67}{\frac{8.1}{\sqrt{23} } }$ ~ $t_2_2$

= -2.368

The value of the test statistics is -2.368.

<em>Now at 0.025 significance level, the </em><u><em>t table gives critical value of -2.074 at 22 degree of freedom for left-tailed test</em></u><em>. Since our test statistics is less than the critical values of t as -2.368 < -2.074, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to </em><u><em>which we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the residents of Legacy Ranch use less water on average.

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3 years ago