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stira [4]
2 years ago
8

The diameter of a wheel of a car is 30cm. If the car travels at an average speed of 13.2m/s, find the number of revolutions made

by the wheel per hour, giving your answer correct to the nearest whole number.
Mathematics
1 answer:
Marysya12 [62]2 years ago
3 0

Answer:

Approximately 50420 revolutions (rounded to the nearest whole number.)

Step-by-step explanation:

Convert the diameter of this wheel to meters: d = 30\; \rm cm = 0.30\; \rm m.

Circumference of this wheel:

\pi \, d = \pi \times 0.30\; \rm m \approx 0.942\; \rm m.

Distance travelled in one hour:

\begin{aligned}v \cdot t &= 13.2 \; \rm m \cdot s^{-1} \times 3600\; \rm s \\ &= 47520\; \rm m\end{aligned}.

Number of revolutions required for covering that distance:

\displaystyle \frac{47520\; \rm m}{(\pi \times 0.30\; \rm m)} \approx 50420.

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Suppose that you measure a pen to be 10.6 cm long. Convert this to meters. Express the length in meters to three significant fig
Travka [436]

Use dimensional analysis:

\frac{10.6cm}{1}*\frac{1m}{100cm}=0.106m

Since we multiplied a numerator and a denominator by centimeters, we are only left with meters.

This answer is already is three significant figures by default.

7 0
3 years ago
Convert 372 in Quinary number​
Romashka [77]
  • Answer:

<em>372₁₀ = 2442₅</em>

  • Step-by-step explanation:

<em>372 : 5 = 74 r 2</em>

<em>74 : 5 = 14 r 4</em>

<em>14 : 5 = 2 r 4</em>

<em>2 : 5 = 0 r 2 ↑</em>

<em>write down the remainders in the reverse order</em>

<em />

<em>372₁₀ = 2442₅</em>

5 0
2 years ago
A miniature quadcopter is located at xi = −1.75 m and yi = −5.70 m at t = 0 and moves with an average velocity having components
Black_prince [1.1K]

The quadcopter's average velocity is given in terms of change in position by

\vec v_{\rm av}=\dfrac{\Delta x}{\Delta t}\,\vec\imath+\dfrac{\Delta y}{\Delta t}\,\vec\jmath

where \Delta x=x_f-x_i, the difference in the quadcopter's final and initial positions and \Delta t=(1.60-0)\,\mathrm s=1.60\,\mathrm s.

The x-component of the average velocity is 2.70 m/s, so

2.70\dfrac{\rm m}{\rm s}=\dfrac{x_f-(-1.75\,\mathrm m)}{1.60\,\rm s}\implies \boxed{x_f=2.57\,\mathrm m}

and the y-component is -2.50 m/s, so

-2.50\dfrac{\rm m}{\rm s}=\dfrac{y_f-(-5.70\,\mathrm m)}{1.60\,\rm s}\implies\boxed{y_f=-9.70\,\mathrm m}

4 0
3 years ago
jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i
FrozenT [24]

Answer:

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length  and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is    2(x +y) = 80

                         x + y =40

                               y = 40 -x

now the area of the rectangle A = length X width

                                                  A = x y

substitute 'y' value in above A = x (40 - x)

                                              A = 40 x - x^2 .....(1)

<u>Step :2</u>

now differentiating equation (1) with respective to 'x'

                                      \frac{dA}{dx} = 40 -2x     ........(2)

<u>Find the dimensions</u>

<u></u>\frac{dA}{dx} = 0<u></u>

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

<u>Step 3</u>:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

\frac{d^2A}{dx^2} = -2

Now the maximum area A =  x y at x =20 and y=20

                                        A = 20 X 20 = 400

                                         

<u>Conclusion</u>:-

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

<u>verification</u>:-

The perimeter = 2(x +y) =80

                           2(20 +20) =80

                              2(40) =80

                              80 =80

8 0
3 years ago
Of those women who are diagnosed to have early-stage breast cancer, one-third eventually die of the disease. Suppose a screening
Finger [1]

Answer:

A) Alternative hypothesis; Ha: p_o > ⅔

B) Null hypothesis;

H0: p_o = ⅔

C) There is sufficient evidence to support the claim that the community screening programme was effective

D) p-value = 0

Its less than the significance value and so we will reject the null hypothesis and conclude that the community screening programme was effective

Step-by-step explanation:

A) We are told that ⅓ of those diagnosed eventually die of the disease. Thus, ⅔ is the fraction that will survive the disease.

Thus, the null hypothesis is;

H0: p_o = ⅔

We are told that a screening programme was started to increase the survival rate. Thus,the alternative hypothesis is;

Ha: p_o > ⅔

B) null hypothesis is;

H0: p_o = ⅔

C) 164 out of the 200 women selected survived the disease.

Thus sample proportion is;

p^ = 164/200

p^ = 0.82

For the z-score value, we will use the formula;

z = (p^ - p_o)/√((p_o(1 - p_o)/n)

Now, p_o = ⅔ = 0.67

Thus;

z = (0.82 - 0.67)/√((0.67(1 - 0.67)/200)

z = 4.51

From online p-value from z-score calculator, we have p-value ≈ 0

This is less than the significant level of 0.05 and therefore we will reject the null hypothesis and conclude that the community screening program was effective.

D) p-value ≈ 0

Reject the null hypothesis

4 0
2 years ago
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