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kirill [66]
3 years ago
9

Write the equation of the parabola y=x^2 + 8x - 51

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0
You already have the equation!  If you want it in vertex form, do this:

y = x^2 + 8x + 16 - 16 - 51, or y = x^2 + 8x + 16 -67, or 
                                                 y = (x+4)^2 - 67.  
The vertex is at (-4,67).
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13
zepelin [54]

Answer:

The required equation is: \mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}

Step-by-step explanation:

We need to find equation from the table given

x     f(x)

3     -5

7     -2

11     1

15    4

We can write equation in the form of y=mx+b

where m is slope and b is y-intercept.

Finding Slope

We can used the slope formula to find slope: Slope=\frac{y_2-y_1}{x_2-x_1}

From the table we have: x_1=3, y_1=-5, x_2=7, y_2=-2

Putting values and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-(-5)}{7-3} \\Slope=\frac{-2+5}{7-3}\\Slope=\frac{3}{4}

So, we get slope m=\frac{3}{4}

Now, finding y-intercept

Using the slope m=\frac{3}{4} and point (3,-5) we can find y-intercept

y=mx+b\\-5=\frac{3}{4}(3)+b\\-5=\frac{9}{4}+b\\b=-5-\frac{9}{4}\\b=\frac{-5*4-9}{4}\\b=\frac{-20-9}{4}\\b=\frac{-29}{4}

The y-intercept is b=\frac{-29}{4}

So, the equation having slope m=\frac{3}{4} and y-intercept b=\frac{-29}{4} will be:

y=mx+b\\y=\frac{3}{4}x-\frac{29}{4}

The required equation is: \mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answer:

The answer is A!

Step-by-step explanation:

Its correct, I took the quiz :)

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