Answer:
(a) 7 essays and 29 multiple questions
(b) Your friend is incorrect
Step-by-step explanation:
Represent multiple choice with M and essay with E.
So:
--- Number of questions
--- Points
Solving (a): Number of question of each type.
Make E the subject of formula in 

Substitute 36 - M for E in 


Collect Like Terms


Divide both sides by -4


Substitute 29 for M in 


Solving (b): Can the multiple questions worth 4 points each?
It is not possible.
See explanation.
If multiple question worth 4 points each, then
would be:

Where x represents the number of points for essay questions.
Substitute 7 for E and 29 for M.


Subtract 116 from both sides



Make x the subject

Since the essay question can not have worth negative points.
Then, it is impossible to have the multiple questions worth 4 points
<em>Your friend is incorrect.</em>
The first number in the bracket is the x coordinate, the second is the y
So substitute the x and y in to get
8=-5(3)+1 which is 8=-14 which isnt true so the answer is no
Answer:
k = 11
Step-by-step explanation:
Given the points are collinear then the slopes between consecutive points are equal.
Using the slope formula
m = 
with (x₁, y₁ ) = (5, 1) and (x₂, y₂ ) = (1, - 1)
m =
=
= 
Repeat with another 2 points and equate to 
with (x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (k, 4)
m =
, then
=
( cross- multiply )
k - 1 = 10 ( add 1 to both sides )
k = 11
We need to graph this equation:

Its solutions are the points through which it graph passes. Since it's a linear equation its graph is a straight line and we only need two of its points to draw it. But before graphing let's re-write the equation. We can substract 16x from both sides:

And we divide both sides by 2:

So now with this equation if we pick two random x values we'll get their corresponding y values. This way we'll find two points that are part of the graph which is the line that passes through both. We can begin with x=0:

So the first point is (0,150). Then we can take x=10 and we get:

So the second point is (10,70). Then the graph is the line that passes through points (0,150) and (10,70). In order to represent it