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Talja [164]
3 years ago
6

Suppose that the average number of accidents occurring on a highway each day is 3.5. Find the probability that at least two acci

dents occur today. Find the probability that at most one accident occurs today.
Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
7 0

Answer: 0.1359

Step-by-step explanation:

This is a Poisson distribution. The formula for calculating Poisson distribution is given as :

P (X = x) = \frac{e^{-λ}λ^{x}}{x!}

λ = 3.5

To find the probability that at most one accident occur today implies that , accident might not happen at all , the maximum accident that can happen is 1, substituting this into the formula , we have

P(X=0) = \frac{e^{-3.5}3.5^{0} }{0!}

P(X=0) = 0.0302

P(X=1) =   \frac{e^{-3.5}3.5^{1} }{1!}

P(X=1) = 0.1057

Therefore , the probability that at most one accident occurs today.

= 0.0302 + 0.1057

= 0.1359

P(x=2) =   \frac{e^{-3.5}3.5^{2} }{2!}

P(X=2) = 0.1850

irina1246 [14]3 years ago
3 0

Answer:

48 yards

Step-by-step explanation:

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