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Olegator [25]
2 years ago
12

WHAT IS THE ANSWER TO -2(y-3)=22

Mathematics
1 answer:
Eva8 [605]2 years ago
8 0
-2(y-3)=22 
-2y+6=22
-2y=16
y=-8
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How do I find the prime factorization of 40? And what is prime factorization?
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Prime factorization is a way of showing which prime numbers (numbers that can only be divided by one and itself) can go into a number. For instance, the prime factorization of 4 would be 2 x 2. Two can only be divided by one and itself, so it is a prime number, and 2 x 2 = 4. For larger numbers, divide by a prime number until the number that is being divided is a prime number. Each divisor will be used as part of the prime factorization. The final dividend will also be used. Add the dividend, order each divisor from least to greatest, and then you're done. Therefore, the prime factorization of 40 would be 2 x 2 x 2 x 5.
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The expression s² is used to calculate the area of a square, where s is the sidelength of the square. What does the expression (
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Answer:

Step-by-step explanation:

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Read 2 more answers
The greatest common divisor of two positive integers less than $100$ is equal to $3$. Their least common multiple is twelve time
tangare [24]

Answer:

129

Step-by-step explanation:

Let a and b be two numbers.

We have been given that the greatest common divisor of two positive integers less than 100 is equal to 3. We can represent this information as GCD(a,b)=3.

Their least common multiple is twelve times one of the integers. We can represent this information as LCM(a,b)=12a.

Now, we will use property GCD(x,y)*LCM(x,y)=xy.

Upon substituting our given values, we will get:

3*12a=ab

36a=ab

Switch sides:

ab=36a

\frac{ab}{a}=\frac{36a}{a}

b=36

Now, we need to find a number less than 100, which is co-prime with 12 after dividing by 3.

The greatest multiple of 3 less than 100 is 99, but it is not co-prime with 12 after dividing by 3.

Similarly 96 is also not co-prime with 12 after dividing by 3.

We know that greatest multiple of 3 (less than 100), which is co-prime with 12, is 93.

Let us add 36 and 93 to find the largest possible sum of the required two integers as:

36+93=129

Therefore, the required largest possible sum of the two integers is 129.

3 0
3 years ago
Find the value: (6 – 12)×(6 – 9)×(6 – 6)×(6 – 3)
natka813 [3]

6-12= -6

6-9= -3

6-6=0

6-3=3

If I'm correct I got 54 bc then u just times all those numbers together

8 0
2 years ago
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