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Archy [21]
3 years ago
5

X-cubed+3x-squared+5x+8/x+1

Mathematics
1 answer:
Blababa [14]3 years ago
4 0
X^3+3x^2+5x+8/x+1
multiply the whole equation by x
x^4+3x^3+5x^2+8+1x
x^4+3x^3+5x^2+x+8
factor out by parts
(x^2-0.641604x+1.33244)(x^2+3.6416x+6.00403)
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Solve for x in the diagram below.
Zielflug [23.3K]

Answer:

3x+45=180

3x=180-45

3x=135

x=45  

Step-by-step explanation:

8 0
3 years ago
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Simplify (ab2 + 10 + a) – (6ab2 – 2ab + 8)
grin007 [14]

−5ab2+2ab+a+2

That is the answer if you need more help on other questions use Math-way it helps answer all problems like that

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5 0
2 years ago
Write and inequality or this statement ; To watch this movie you must be at least 17 years old ?
julia-pushkina [17]

Answer:

x<u>></u>17

Step-by-step explanation:


5 0
3 years ago
let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0
1 year ago
PLEASE HELPPPP
Studentka2010 [4]

Answer:

1774.67π mm³

Step-by-step explanation:

Please find attached to this question, the required diagram.

From the question, we are told we have a spherical mold.

We would find the volume of a spherical mold using the formula for the volume of a sphere.

The volume of a sphere is calculated as : 4/3πr³

From the attached diagram, we are given the Diameter do the spherical mold as: 22mm

Radius of the spherical mold = Diameter ÷ 2 = 22mm÷ 2 = 11mm

The volume of the spherical mold = 4/3 × π × 11³

= 1774.6666667π mm³

Approximately and leaving it in terms of pi (π)= 1774.67π mm³

5 0
4 years ago
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