(2,4)
I marked them on coordinate plane
Answer:
The angle bisector is construct.
Step-by-step explanation:
We used the geogebra.org site. We first constructed a large triangle with acute angles. Then from point A we made a semicircular section to its sides. At the intersection of the sides and the semicircular section, we construct two circles so that they intersect. Then from the point A we draw a line through the intersection of the circles and thus we obtain the bisector of the angle.
We repeat the same procedure for point B and for point C. In this way, we obtain a bisector for all angles of a triangle.
Answer:
its c.
Step-by-step explanation:
because when you add opposites its always zero
hope this helps
9514 1404 393
Answer:
a) profit has a typical curve: negative at low volume, and again at very high volume.
b) $239,407
Step-by-step explanation:
a) The graph is negative below x=1.58, so the break-even point is 158 toys sold. The profit declines steeply above 533 toys sold, to again go negative for 774 toys sold. This sort of curve seems fairly typical.
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b) The profit is a maximum of $239,407 when 533 toys are sold.
The volume of the cube is base times width times height, or any of these measurements cubed, since they're all the same.
Therefore, the volume of the cube is:
12³ = 1728 in³
The volume of the cylinder is π*r²*h, where r is the radius and h is height
Remember that the diameter is twice the radius, so the radius is 2 in and the height is 5 in.
Therefore, each can has a volume of π * 2² * 5 = 20π
Approximating π as 3.14....
The volume of each can is 62.8 in³
1728 ÷ 62.8 = 27.5
Rounding down, 27 cans can fit in the crate.
This is how I suspect the teach wanted you to solve, since it involves finding the volume of both shapes and using pi. However, this is not actually how many cans can fit, because it does not take into account the fact that not every inch of available space will be used.
Here is another way to solve,taking this fact into account, that gives the more accurate answer:
Each can has a diameter of 4in, which means that they each require a square of 4 x 4 in to accommodate their base.
The base of each can requires 16 in² of space in the crate.
The base of the cube is 12 x 12, so the area of the base is 144 in²
144 ÷ 16 = 9, so the base of the cube, or bottom of the box, can fit 9 cans, arranged 3 by 3.
The cube has a height of 12 inches, and each can is 5 inches tall. Therefore, two of these stacks can fit in the box, for 9 x 2 = 18 cans.
This is a much better answer, as it takes into account the fact that the cans can't occupy every inch of available space in the cube.
