All categories

3 years ago

Write a quadratic function f whose zeros are 4 and 3 .

Mathematics

1 answer:

Pani-rosa [81]3 years ago

5 0

F(x) = (x-4)(x-3)

if you put x=4, it makes f(x) 0. if you put x=3 it makes f(x) 0

You might be interested in

Can someone help me on 6 or 7 (40 points)

adelina 88 [10]

So I think that number 6 is just dividing by 3 and the second one doesn't like divide so number 7 is no and number 6 is yes

7 0

2 years ago

Read 2 more answers

What is the percentage of lemons in this group of lemons and strawberries?

tiny-mole [99]

Answer:

50%

Step-by-step explanation:

6 0

3 years ago

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

The point $(1\frac{1}{2},1)$ won't be on the graph because the corresponding value of y for $x = 1\frac{1}{2}$ is $y = 2\frac{1}{4}$

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

The point $(4,6)$ would be on the graph because the corresponding value of y for $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

The point $(18,12)$ wouldn't be on the graph because the corresponding value of y for $x = 18$ is $y = 12$

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

The point $(0,0)$ would be on the graph because the corresponding value of y for $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

The point $(2\frac{1}{2},3\frac{3}{4})$ would be on the graph because the corresponding value of y for $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

2 years ago

A box contains 5 blue balls, 2 white balls and 3 black balls. A ball is chosen randomly. Find the probability that the chosen ba

Nimfa-mama [501]

Answer:

7/10 or 70%

Step-by-step explanation:

Add the number of each color of balls together to get the total

5 + 2 + 3 = 10

Add the number of all the balls that aren't black

5 + 2 = 7

Then divide how many balls that aren't black by the total. This gives us the probability the ball you choose is not black

7/10 = 0.7 or 70%

5 0

3 years ago

Can someone please help!!!

Delvig [45]

Answer:

f(1) = 5, f(2) = 8, f(3) = 11

Step-by-step explanation:

Common difference refers to how you get from one value in the sequence to the next.

If f(0) = 2, f(1) = 2 + 3 = 5 etc

8 0

3 years ago