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Olenka [21]
3 years ago
11

Write a quadratic function f whose zeros are 4 and 3 .

Mathematics
1 answer:
Pani-rosa [81]3 years ago
5 0
F(x) = (x-4)(x-3)

if you put x=4, it makes f(x) 0. if you put x=3 it makes f(x) 0
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Answer:

The answer is 2178, if you multiply it by 4, you would get 8717

Step-by-step explanation:

HERE ARE THE STEPS IF YOU NEED THEM!!

1. Lets say the number is written as ABCD (1000a+100b+10c+d).

2.Multiplying it by 4, gives you DCBA (1000d+100c+10b+a)

3. By divisibility of 4, BA is a two-digit number divisible by 4.

4.Now, the largest possible value of ABCD is 2499, because anything more will result in a five digit number when multiplied by 4.

5. Out of the two possibilites 1 and 2 for A, [3] follows that A is even, so 2.

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7. Using [2], 4000a+400b+40c+4d = 1000d+100c+10b+a, which would simplify to 2c-13b = 1 after substituting A = 2 and D = 8.

8.The only possible value of (b,c) where they would both be single digit integers is (1,7). Also to note from [3], B is odd. And from [4], B is either 1 or 3.

6 0
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