Answer:
Step-by-step explanation:
Given
In ABC;
Required
Determine side F
In the given question;
DEF is a dilation of ABC
Comparing both triangles side by side,
Side F is a direct dilation of side C and this is calculated as follows
Answer:
im thinking the answer is B. 3
Step-by-step explanation:
What are the answers being provided ?
Answer:
team loss after three games is 5.
Step-by-step explanation:
we will use positive sign for gain and negative sign for loss.
Given
Jim's team gained 7 yards on the first play
gain of yards = +7
lost 2 yards on the second play
loss of yards = -2
lost 10 yards on the third play
loss of yards = -10
Total yards gain or lost by Jim's team = +7 + (- 2) + ( - 10)
Total yards gain or lost by Jim's team = +7 -2 -10 = -5
sine sign is negative, it means there is loss and the net loss is 7 yards.
Thus, team loss after three games is 5.
Answer:
Step-by-step explanation:
Gotta love these motion problems!!! This one is especially tricky! At noon, ship A is 180 km west of ship B. If ship A is traveling east, it is closing its distance to ship B (if ship B didn't move). But ship B is moving north at the same time. We need to find the distance each can travel in 4 hours using the d = rt formula. For ship A. We know it's moving at 35 km/h, so in 4 hours it can move d = 35(4) which is 140 km. Remember that is closing the distance to ship B. So it is 180 - 140 directly south of ship B. This problem will turn out to be a right triangle problem of sorts. The distance of 40 km serves as the base of this right triangle.
With ship B moving north at 25 km/hr, it can travel d = 25(4) which is 100 km. This serves as the height of the triangle. We are asked to find the rate at which the distance is changing 4 hours from their starting points. We know how far each can travel in those 4 hours, so in order to find the rate of change (which is the same thing as the slope!), we take the height and divide it by the base because that is the same thing as taking the rise over the run. 100/40 is 10/4 which is a rate of change of 2.5 km/hr
