The formula can be used to determine how many students are required to earn $1,500 in profit.t:
5.n - 100 - 200 = 1500.
<h3>What is linear equation?</h3>
An equation is deemed to be linear if a variable's maximum power consistently equals 1. Another name for it is a one-degree equation. The form of the linear equation Ax + B = 0 is standard for one-variable linear equations. In this instance, as well as A are variables while B is a constant.
Ax + By = C is the standard form of a two-variable linear equation. This equation contains the variables x and y, the coefficients Both a B, as well as the constant C.
<h3>According to the given data:</h3>
Given that the no. of students is n.
DJ charge - $200 Decorations cost - $100
Charge each student should pay - $5.00
Therefore the equation that find the no. of students to make a profit of $1,500.5.n - 100 - 200 = 1500
To learn more about linear equation visit:
brainly.com/question/2030026
#SPJ9
Answer:
-x
Step-by-step explanation:
Answer:
Using the concept of speed-distance-time, we find that the diameter of the circular path is 12 inches.
Step-by-step explanation:
Given that the object completes one revolution in 8 seconds. So, the circular speed of the object is 2πr/8 = πr/4 inches per seconds, where r is the radius of the circular path. The speed can be written as:
πr/4 inches per seconds = 60πr/4 inches per minute = 15πr inches per minute.
But, it is given that the circular speed of the object is 90π inches per minute. So,
90π = 15πr
r = 6 inches
Since, diameter is the double of radius, d = 2r = 12 inches.
For more explanation, refer the following link:
brainly.com/question/17978382
#SPJ10
Answer:
11.9 miles
Step-by-step explanation:
The length of the track is ...
C = 2πr = 2π(200 ft) = 400π ft
Then the length of 50 laps will be ...
50C = 50·(400π ft) = 20,000π ft ≈ 62,831.9 ft
The number of miles (m) this is can be found from ...
m(5280 ft) = 62,831.9 ft
m = 62,831.9/5280 ≈ 11.90 . . . . miles
50 laps is about 11.9 miles.
Hey there mate :)
Please check the attached image for answer.