Answer:
3n^2+9+5n^4+55n
Step-by-step explanation:
Steps
$\left(3n^2+9+5n^4-3n\right)+\left(-9n\left(-7\right)-5n\right)$
$\mathrm{Remove\:parentheses}:\quad\left(a\right)=a,\:-\left(-a\right)=a$
$=3n^2+9+5n^4-3n+9n\cdot\:7-5n$
$\mathrm{Add\:similar\:elements:}\:-3n-5n=-8n$
$=3n^2+9+5n^4-8n+9\cdot\:7n$
$\mathrm{Multiply\:the\:numbers:}\:9\cdot\:7=63$
$=3n^2+9+5n^4-8n+63n$
$\mathrm{Add\:similar\:elements:}\:-8n+63n=55n$
$=3n^2+9+5n^4+55n$
When two lines intersects, they have a plane common to
both of them, hence we can say that both the lines lie in the same plane.
So, the given statement is True
9514 1404 393
Answer:
(-∞, 2-√7) ∪ (2+√7, ∞)
Step-by-step explanation:
The factored form of a polynomial is helpful for solving related inequalities. For quadratics with two real zeros, the sign changes at each zero. If the leading coefficient is positive, the sign is positive to for x-values "outside" either zero, and is negative between the zeros.
Your inequality can be written in standard form as ...
x² -4x -3 > 0
x² -4x +4 -7 > 0
(x -2 -√7)(x -2 +√7) > 0 . . . . . factor the difference of squares (x-2)² -7
The zeros are at x=2-√7 and x=2+√7, so the product of these factors will be positive for x < 2-√7 and x > 2+√7. The solution in interval notation is ...
(-∞, 2-√7) ∪ (2+√7, ∞)
_____
<em>Additional comment</em>
We suspect a typo in the problem statement. If it were to read ... > -3, then the zeros would be at 1 and 3, and the solution would be (-∞, 1)∪(3, ∞).
= (16x3 - 8x2 + 4x4) / 2x
= 4x * (4x2 - 2x + x3) / 2x
= 2 * (4x2 - 2x + x3)
= 8x2 - 4x + 2x3
Answer A
Step-by-step explanation:
So I'm not exactly sure what you're asking here, but from my understanding, you would do...
(42,672/4) ÷ (37,426/4)
Which would be...
10668 ÷ 9356.5
And then...
21336/18713 or a random decimal. So I really don't know if I understood your question. But remind me if this is wrong!