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3 years ago

How to find the mixed number of 4.216

Mathematics

2 answers:

daser333 [38]3 years ago

5 0

4 and 216 over a thosuand

Kryger [21]3 years ago

4 0

To find a mixed number from a decimal u basically just keep the whole number and put everything to the right of the decimal point as the numerator. the denominator is just a 1 with however many digits there are. for example, 4.216 would be 4 216/1000. from there, u just simplify it :)

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Asap I will fail it’s due soon

Elan Coil [88]

Answer:

See explanation

Step-by-step explanation:

1. From the graph of absolute value function:

a. The domain is $x\in (-\infty, \infty)$

b. The range is $y\in [0,\infty)$

c. The graph is increasing for all $x>0$

d. The graph is decreasing for all $x$

2. From the graph of quadratic function:

a. The domain is $x\in (-\infty, \infty)$

b. The range is $y\in (-\infty,0]$

c. The graph is increasing for all $x$

d. The graph is decreasing for all $x>0$

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3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

Deana bought 12 packages of batteries. Some of the packages contained 4 batteries and some contained 6 batteries. She bought a t

NARA [144]

Answer:

She bought 7 battery packs containing 6 batteries

Step-by-step explanation:

4bx5= 20 batteries

6bx7=42 batteries

42+20=62

7 0

3 years ago

Determine whether the equation below has a one solutions, no solutions, or an

lesantik [10]

The equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions

<h3>How to determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions?</h3>

The equation is given as:

x + 2 = 2 + x

Collect the like terms

x - x =2 - 2

Evaluate the like terms

0 = 0

An equation that has a solution of 0 = 0 has an infinite number of solutions

Possible values of x are x = 8 and x = -8

Hence, the equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions

Read more about number of solutions at

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2 years ago

A square with an area A2 of is enlarged to a square with an area of 25A2. How was the side of the smaller square changed?

makvit [3.9K]

Given:
a square with an area of a² is enlarged to a square with an area of 25a².

The side length of the smaller square was changed when The side length was multiplied by 5.

Area = (1a)² = a²
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3 0

4 years ago

Read 2 more answers