<span>.58 is the answer, first u do the 3 part then mulitply that times 8 then divide by 8 :)</span>
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Okay so like, all you've gotta do is multiply 567 by 48 & add 1250. Leaving you with the answer of 28,466
Answer:
(4, 7/2)
Step-by-step explanation:
Take the mean of the x-coordinates and the mean of the y-coordinates.
x = (-1 + 9)/2 = 8/2 = 4
y = (2 + 5)/2 = 7/2
Answer: (4, 7/2)
